Answer:
50 days
Step-by-step explanation:
2500/50 = 50
Answer: 50 days
Answer:
Step-by-step explanation:
<u>Key skills needed: Explicit formula, Geometric sequence</u>
1) This is a geometric sequence, meaning a constant (like 6 or 3.5) is being multiplied to every term. First we need to find the constant.
This can be done by doing -42 ÷ 7 or 252 ÷ -42
-42 ÷ 7 equals -6.
252 ÷ -42 also equals -6.
2) This means that constant is -6.
3) The general form for an explicit formula of a geometric sequence is:
--> r means the constant (or common ratio) that is being multiplied.
--> 
means the first term
--> 
means the "nth" numbered term (so 
is the 3rd term, 
is the 10th term and so on).
--> 
is just the "n" in minus 1.
4) We can use this formula to create an explicit formula for the geometric sequence in the problem.
--> 
(Since we got -6 as the constant/common ratio).
--> 
(Since 7 is the 1st term)
This means that our formula would be -->
<em>Hope you understood and have a nice day!! :D</em>
52/8 = 6
6*8 = 48
52-48 = 4
So 52 = 6*8+4
The quotient is 6, the remainder is 4.
Answer:
x=4 x=10
Step-by-step explanation:
(x - 6) (x - 8) =8
We need to multiply out the left side
x^2 -8x -6x+48 = 8
x^2 -14x +48 = 8
Subtract 8 from each side
x^2 -14x +48-8 = 8-8
x^2 -14x+40 =0
We need to factor the left side. What two numbers multiply to give 40 and add to give -14
-4*-10 = 40
-4+-10 = -14
(x-4) (x-10) =0
Using the zero product property
x-4=0 x-10 =0
x=4 x=10
A = event the person got the class they wanted
B = event the person is on the honor roll
P(A) = (number who got the class they wanted)/(number total)
P(A) = 379/500
P(A) = 0.758
There's a 75.8% chance someone will get the class they want
Let's see if being on the honor roll changes the probability we just found
So we want to compute P(A | B). If it is equal to P(A), then being on the honor roll does not change P(A).
---------------
A and B = someone got the class they want and they're on the honor roll
P(A and B) = 64/500
P(A and B) = 0.128
P(B) = 144/500
P(B) = 0.288
P(A | B) = P(A and B)/P(B)
P(A | B) = 0.128/0.288
P(A | B) = 0.44 approximately
This is what you have shown in your steps. This means if we know the person is on the honor roll, then they have a 44% chance of getting the class they want.
Those on the honor roll are at a disadvantage to getting their requested class. Perhaps the thinking is that the honor roll students can handle harder or less popular teachers.
Regardless of motivations, being on the honor roll changes the probability of getting the class you want. So Alex is correct in thinking the honor roll students have a disadvantage. Everything would be fair if P(A | B) = P(A) showing that events A and B are independent. That is not the case here so the events are linked somehow.
