Danville,Keflavik,Somerville,Ulsan,,Smithfield
X-y=2 (*-2) --> -2x+2y=-4
2x+3y=14
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2x+3y=14
-2x+2y=-4
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5y=10
y=2
<span>The graph is attached.
Explanation:We can use the x- and y-intercepts to graph. The x-intercept of the first equation is 8, and the y-intercept is 8. The x-intercept of the second equation is -2, and the y-intercept is 2.
<span>
x-intercepts are where the data crosses the x-axis. At every one of these points, the y-coordinate will be 0; therefore we can substitute 0 for y and solve to get the value of the x-intercept.
For the first equation, we would have
8x+8(0)=64
8x=64.
Divide both sides by 8:
8x/8 = 64/8
x=8.
For the second equation,
2x-2(0)=-4
2x=-4.
Divide both sides by 2:
2x/2 = -4/2
x=-2.
y-intercepts are where the data crosses the y-axis. At every one of these points, the x-coordinate will be 0; therefore we can substitute 0 for x and solve to get the value of the y-intercept.
For the first equation,
8(0)+8y=64
8y=64.
Divide both sides by 8:
8y/8 = 64/8
y=8.
For the second equation,
2(0)-2y=-4
-2y=-4.
Divide both sides by -2:
-2y/-2 = -4/-2
y=2.
Plot these points for both equations and connect them to draw the line.</span></span>
Answer:
Center of the circle= (-9,6)
Radius = 5 units
Step-by-step explanation:
Once the equation of the circle has been written in the format
(x-h)²+(y-k)²=r² , (h,k) is the center while r is the radius of the circle.
From the given equation, -h=9 therefore h= -9.
-k = -6 therefore k = 6. r² = 25 therefore r= √25=5
Center of the circle= (-9,6) radius = 5 units