We are asked in the problem to deterimne the point slope form that is y - y1 = m(x-x1),. Substituting, m = 3 and x1 = 2
Translating,
y + a = 3*(x-2).
Ahnswer to this problem then is C.
Cot(3x)=3^(1/2)
cot(x)= cos(x)/sin(x)
cot(3x)= cos(3x)/sin(3x)
look at a unit circle chart
find a value for cos that has sqrt(3) in it
which one will reduce so that the cos/sin will equal sqrt(3)?
pi/6 radians
now cot(3x) implies that x is one third this value
pi/18 is the answer
The answer is B i had this problem.
Factor out the cos<span>θ:
</span>cosθ (2sin<span>θ + sqrt3) = 0
</span>Therefore, the only ways this can happen are if either cosθ = 0 or if (2sin<span>θ + sqrt3) = 0
</span>The first case, cosθ = 0 only at θ <span>= pi/2, 3pi/2.
</span>The second case, <span>(2sin<span>θ + sqrt3) = 0 simplifies to:
</span></span>sin<span>θ = (-sqrt3)/2
</span><span><span>θ = 4pi/3, 5pi/3
</span></span><span><span>Therefore the answer is A.
</span></span>
The coordinates of C is, (3,-1)
A is the. Answer
