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saul85 [17]
3 years ago
14

Find angle c° and d°.

Mathematics
1 answer:
Vladimir79 [104]3 years ago
7 0

Answer:

b

Step-by-step explanation:

You might be interested in
A company has developed a new type of light bulb, and wants to estimate its mean
BARSIC [14]

Answer:

628

Step-by-step explanation:

We have the standard deviation of the sample, so we use the t-distribution to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 12 - 1 = 11

95% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 11 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.95}{2} = 0.975. So we have T = 2.2

The margin of error is:

M = T\frac{s}{\sqrt{n}} = 2.2\frac{59}{\sqrt{12}} = 37

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 665 - 37 = 628 hours.

The answer is 628

4 0
3 years ago
3+126 - 4( 526) -(4x) does it have a solution​
natali 33 [55]
3 + 126 - 4• 526 - (4x)
3 + 126 -2104 -4x

-4x -1975
5 0
3 years ago
Help needed asap graph posted below
Aloiza [94]
Answer: D) (x+1)(x + 2)(x-3)

This is because the roots are x = -1, x = -2 and x = 3
Simply get all the numbers to each side to have 0 on the right side

x = -1 turns into x+1 = 0
x = -2 turns into x+2 = 0
x = 3 turns into x-3 = 0

The three factors are (x+1), (x+2) and (x-3)
Which leads to (x+1)(x+2)(x-3)

6 0
3 years ago
Which sequences are geometric? Check all that apply.
zhenek [66]

Answer:

The sequences which are geometric are

16,-8,4,-2,1

625,125,25,5,1

-15,-18,-21.6,-25.92,-31.104

Step-by-step explanation:

Geometric sequences are ones in which you multiply or divide to get the next terms in the sequence.

Cheers

7 0
3 years ago
If X denotes the number of heads in n tosses of a coin, what is the standard deviation of the random variable X? Does this stand
vfiekz [6]

Answer:

\sigma=\sqrt{np(1-p)}=\sqrt{n*0.5(1-0.5)}=\frac{\sqrt{n}}{2}

As we can see the deviation is proportional to the value of n and if n increase then the deviation increases too. So then the deviation would be larger when n gets larger.

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

The probability mass function for the Binomial distribution is given as:  

P(X)=(nCx)(p)^x (1-p)^{n-x}  

Where (nCx) means combinatory and it's given by this formula:  

nCx=\frac{n!}{(n-x)! x!}  

Solution to the problem

We can define the following random variable X ="Number of heads in n tosses of a coin".

We assume that the coin is fair and then P(H)= 0.5 for any trial so then we can model X with the following distribution:

X \sim Bin (n, p=0.5)

For this distribution the mean and variance are given by:

E(X)=np=n*0.5=\frac{n}{2}

Var(X)= np(1-p) = n*0.5*(1-0.5) = 0.25 n = \frac{n}{4}

And the deviation would be just the square root of the variance and we got:

\sigma=\sqrt{np(1-p)}=\sqrt{n*0.5(1-0.5)}=\frac{\sqrt{n}}{2}

Does this standard deviation get larger or smaller when n gets larger?

As we can see the deviation is proportional to the value of n and if n increase then the deviation increases too. So then the deviation would be larger when n gets larger.

3 0
3 years ago
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