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RUDIKE [14]
3 years ago
7

charity is four times as old as her daughter. she is also six years younger than her husband. The sum of their ages ten years to

come will be 117 years. How old is Charity today?​
Mathematics
1 answer:
Pachacha [2.7K]3 years ago
5 0

Answer:

36years

Step-by-step explanation:

Let charity present age be x

Charity daughter present age be y

Charity husband present age be z

If the sum of their ages ten years to come is 117, then;

10+x+10+y+10+z = 117

30+x+y+z = 117

x+y+z = 87 ... 1

If charity is four times as old as her daughter, then;

x = 4y

y = x/4 ... 2

If she is also six years younger than her husband, then;

x = z- 6

z = x+6 .. 3

Substitute 2 and 3 into 1;

x + x/4 + (x+6) = 87

Multiply through by 4

4x + x + 4(x+6) = 4(87)

5x+4x+24 = 348

9x = 348 - 24

9x = 324

x = 324/9

x = 36

hence Charity is 36years old today

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The missing value should be 48 because between the two numbers of each group. They are multplied by 6

Step-by-step explanation:

Hope this Helped!

7 0
3 years ago
Read 2 more answers
How do I solve this?​
lakkis [162]

Answer:

\large\boxed{4\sqrt{-81}+\sqrt{-25}=41i}

Step-by-step explanation:

i=\sqrt{-1}\\\\\sqrt{-81}=\sqrt{(81)(-1)}=\sqrt{81}\cdot\sqrt{-1}=9i\\\\\sqrt{-25}=\sqrt{(25)(-1)}=\sqrt{25}\cdot\sqrt{-1}=5i\\\\4\sqrt{-81}+\sqrt{-25}=4(9i)+5i=36i+5i=41i

3 0
3 years ago
How does f(x) = 3 ^x change over the interval x = 4 to x= 5
zloy xaker [14]

Answer:

f(x) = 3^x increases steadily on the interval [4,5].

Step-by-step explanation:

This exponential function f(x) = 3^x has a positive base (3) which is larger than 1.  Thus, this function continues to increase as x increases, including the case where x increases from 4 to 5.

6 0
3 years ago
One solution to the problem below is 5 what ya the other solution a^2-25=0
Alex

-5

a^2-25=0

a^2=25

take the square root of both sides

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Help please ASAP
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B Beacuse b best fits the suituation
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