Answer:
5^12 or (244140625)
Step-by-step explanation:
I've always hated exponents but the way I visualize this is essentially taking 5^4 and multiplying it by itself 3 times (because it is put to the power of 3).
(5^4)·(5^4)·(5^4)
when you do this you can just add the exponents together
5^(4+4+4)
5^12
Answer:
8x + 20 ≥ 25
Step-by-step explanation:
Well 8 times the sum of a number "x" plus 20,
So we can write the following,
8x + 20
and that should be greater than or equal to 25
8x + 20 ≥ 25
<em>Thus,</em>
<em>as an inequality it is 8x + 20 ≥ 25.</em>
<em />
<em>Hope this helps :)</em>
Answer:
5-18 answers below ↓
Step-by-step explanation:
5) 14/2=7
7^2=49
10^2=100
h^2+49=100
-49 -49
h^2=51 h=✓51= 3•17
6) 48/2= 24
24^2=576
44^2=1936
h^2+576=1936
-576 -576
h^2=1360 h=✓1360= 4•340
7) 24^2+b^2=32^2 (leg is short side & hypo.. is long side)
576+b^2=1024
-576 -576
b^2= 448 b=✓448=4•112 length of 3rd side it's hypo..
8) 24^2+b^2=45^2
576+b^2=2025
-576 -576
b^2=1449 b=✓1449=9•161 length of 3rd side hypo..
9) 40^2+b^2=85^2
1600+b^2=7225
-1600 -1600
b^2=5625 b^2=✓5625 b=75 length of 3rd side leg
10) 49^2+b^2=168^2
2401+b^2=28,224
-2401 -2401
b^2=25,823 b=✓25,823 b=49•527 length of 3rd side hypo..
11) 72^2+b^2=78^2
5184+b^2=6084
-5184 -5184
b^2=900 b=✓900=30 length of 3rd side leg
12) 7^2+x^2=10^2
49+x^2=100
-49 -49
x=51=3•17
13) 12^2+x^2=28^2
144+x^2=784
-144 -144
x=✓640=4•160
14) 44^2+x^2=52^2
1936+x^2=2704
-1936 -1936
x=✓768=4•192
15) 120^2+h^2=125^2
14,400+h^2=15,625
-14,400 -14,400
h^2=1,225 h=✓1225 h=35
16) might be wrong but worth a try 8+8=16
16^2+x^2=16^2
256+x^2=256 x=0 don't know these challenge ones sorry, but the rest of the questions are correct hope this helps u (:
2/3 of 13 is 8. The answer would be 8. If you want to be exact, it would be 8.66666666667.
Have a great day!
-Pepetreefrogthe2nd
Answer: 
Step-by-step explanation:
By definition, negative numbers, positive numbers and zero are Integers.
It is important to remember the multiplication of signs:
You can observe that you must multiply two integers, one of them is negative and the other one is positive. The product will be an integer. Then:
Since any Integer can be written as a fraction, you can rewrite the product by writing 
as the numerator and 
as the denominator.
Then, this is:
