A² = b² + c² - 2bc cosA
a² = 10² + 14² - 2*10*14 cos54
a² = 100 + 196 - 280 * cos54
a =
a = 11.46
9514 1404 393
Answer:
132°
Step-by-step explanation:
Name the vertex of each angle the same as the angle letter. Name the intersection of the "horizontal" and "vertical lines" point Q.
Angle ZXQ is vertical to ∠x, so is the same measure.
Angle YQX is the value that makes the sum of angles in triangle XYQ be 180°. That is ...
∠YQX = 180° -51° -57° = 72°
This is also the measure of its vertical angle in the other triangle. Angle z is the sum of that vertical angle and 60°, so we have ...
∠z = 72° +60°
∠z = 132°
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<em>Additional comment</em>
The relations we used are ...
- vertical angles are congruent
- sum of angles in a triangle is 180°
- an exterior angle is equal to the sum of the remote interior angles
You would do 29.85 ÷ 3 which equals 9.95. You would do the in verse operation. Hope I helped you.
The correct answers are 1. D, 2. A, 3. A, 4. A, 5. A
N=1/2MP? Since n would be the midpoint you have to divide the segment into two.
