Does anyone know what the rule for the 2 and 3 table could be

Mathematics

1 answer:

ipn [44]3 years ago

5 0

Answer:

table 2= could be multiply each of the numbers by 4

table three= plug the x value in the equation and the y into the equation and then just solve it and make sure you add eight before you put your answer in.

Step-by-step explanation:

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Please please help me

Gekata [30.6K]

Answer:

$\large\boxed{\dfrac{\boxed{8}}{81}}$

Step-by-step explanation:

$\text{If}\ a_1,\ a_2,\ a_3,\ a_4,\ ...,\ a_n\ \text{is the geometric sequence, then}\\\\\dfrac{a_2}{a_1}=\dfrac{a_3}{a_2}=\dfrac{a_4}{a_3}=...=\dfrac{a_n}{a_{n-1}}=constant=r-\text{common ration}.\\\\\text{We have}\ \dfrac{1}{2},\ \dfrac{1}{3},\ \dfrac{2}{9},\ \dfrac{4}{27},\ ...\\\\\dfrac{\frac{1}{3}}{\frac{1}{2}}=\dfrac{1}{3}\cdot\dfrac{2}{1}=\dfrac{2}{3}\\\\\dfrac{\frac{2}{9}}{\frac{1}{3}}=\dfrac{2}{9}\cdot\dfrac{3}{1}=\dfrac{2}{3}\\\\\dfrac{\frac{4}{27}}{\frac{2}{9}}=\dfrac{4}{27}\cdot\dfrac{9}{2}=\dfrac{2}{3}$

$\bold{CORRECT}\\\\\dfrac{x}{\frac{4}{27}}=\dfrac{2}{3}\qquad\text{multiply both sides by}\ \dfrac{4}{27}\\\\x=\dfrac{2}{3}\cdot\dfrac{4}{27}\\\\x=\dfrac{8}{81}$

8 0

3 years ago

Examine the inequality and its graph. Which values are part of the solution set? Check all that apply.

german

Answer:

Step-by-step explanation:

8 0

4 years ago

Read 2 more answers

graph the solution to the following system of inequalities y<-2x+7, y greater than or equal to 2x - 3

Alex777 [14]

Answer:

See attached diagram

Step-by-step explanation:

Graph the solution of the inequality $y$ First, draw the dotted line $y=-2x+7$ (dotted because the sign of the inequality is <). Then determine wich part of the coordinate plane should be shaded. Since the origin's coordinates satisfy the inequality, then this point should belong to the region (red part on the diagram).

Graph the solution of the inequality $y\ge 2x-3.$ First, draw the solid line $y=2x-3$ (solid because the sign of the inequality is ≥). Then determine wich part of the coordinate plane should be shaded. Since the origin's coordinates satisfy the inequality, then this point should belong to the region (blue part on the diagram).