Salivary amylase will be active for only an hour or so because the optimum pH for activity of amylase is about 6.7–7.0 which is available in the mouth but the pH of the stomach is acidic around 1-2 due to which the amylase enzyme becomes inactive in short-time.
The lingual lipase enzyme is present in the saliva but isn't active until reaching the stomach because this enzyme is acid stable and works efficiently in the stomach, not in the mouth.
Amylase enzyme is secreted in the mouth and is responsible for the breakdown of starch in food into sugars and it starts acting as soon as we put food in the mouth whereas Lingual lipase enzyme is secreted along with saliva but it is not active in the mouth rather its activity starts in the stomach which is responsible for the degradation of triacylglycerol molecules.
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Answer:
The correct answer will be- phloem transports photsynthetic products to the roots
Explanation:
Phloem is the vascular tissue which specializes in transporting the solute molecules like sugar in the form of sucrose to in the plants.
The phloem connects the photosynthetic organ (Leaves) to non-photosynthetic organs (stem and roots) of the plants by transporting the photosynthates or sucrose to various parts.
Since the roots also need the energy to perform metabolic functions so need the photosynthates to synthesize the energy molecule. They receive the photosynthates from the phloem.
Thus, phloem transports photosynthetic products to the roots is the correct answer.
Answer:
Explanation:
hepatic portal vein is a blood vessel that carries blood from the gastrointestinal tract and spleen to the liver. This blood are usually rich in nutrient because it contains extraction from digested materials or food substances in the gastrointestinal tract and it is processed in the liver for removal of toxins before the blood returns to the heart.
Answer:
Exponential Growth: y = a(1 + r)x
Exponential Decay: y = a(1 - r)x
Explanation:
Remember that the original exponential formula was y = abx.
You will notice that in these new growth and decay functions,
the b value (growth factor) has been replaced either by (1 + r) or by (1 - r).
The growth "rate" (r) is determined as b = 1 + r.
The decay "rate" (r) is determined as b = 1 - r
