Help plz

Mathematics

1 answer:

AlekseyPX3 years ago

4 0

Assuming x is what your looking for x=48(3)+28

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You reach into a bag of coins and withdraw two coins. What is the probability you withdrew a nickel and then a dime if the bag h

VMariaS [17]

14/19 if you add the amount of nickels and dimes together and then for the denominator just add all of the coins together.

5 0

3 years ago

Write a quadratic function f whose zeros are - 5 and 7.

weeeeeb [17]

Our two binomials are (X-5)(X-7)

If we FOIL those two terms [x*x = x2; x*-7 = -7x; x*-5 = -5x; -5*-7 = 35] and combine the like terms, we're left with one of many quadratic function
Answer
x2-12x+35

3 0

4 years ago

The pie chart shows information about voters in an election. 2800 more women vote than men. Work out the total number of voters.

Dmitry [639]

The picture in the attached figure

let
x--------> men voters
y-------> women voters

we know that
y=x+2800------> y-x=2800------> equation 1

step 1
find the percentage of women and men voters
in the graph
central angle by men voters=130°
central angle by women voters=(360°-130°)-------> 230°
by using proportion
men voters
$\frac{360}{100} = \frac{130}{M} \\ M=(100*130)/360 \\ M=36.11$ %

women voters
$\frac{360}{100} = \frac{230}{F} \\ F=(100*230)/360 \\ F=63.89$ %

remember equation 1
y-x=2800
so
F-M=63.89%-36.11%----> 27.78%

if 27.78% correspond to 2800 voters
100%---------------------->T
T=100*2800/27.78-------> T=10,079.19 voters

the answer is
about 10,079 voters

6 0

4 years ago

I GIVE BRAINLIEST PLS HELP

ioda

The answer is 8
Here's why:
${ ( \frac{( {6}^{7}) \times ( {3}^{3}) }{( {6}^{6}) \times ( {3}^{4} ) } )}^{3} = \\ ( \frac{6}{3} ) ^{3} = \\ \frac{216}{27} = 8$
The exponents are subtracted one from another when divided.
$\frac{ a ^{b} }{ {a}^{c} } = {a}^{b - c}$
We can look at the problem this way:
$( \frac{6^{7} }{6 ^{6} } \times \frac{3^{3} }{ {3}^{4} } ) = (6^{7 - 6} \times {3}^{3 - 4} ) = \\ ({6}^{1} \times {3}^{ - 1} )$
Since we have the power of -1 on the 3, we apply this rule:
${a}^{ - b} = \frac{1}{ {a}^{b} }$
Also this rule because we have the power of 1 on the 6:
${a}^{1} = a$
Then we get this:
$(6 \times \frac{1}{3} )^{3} = ( \frac{6}{3} )^{3}$
We apply the rule:
$( \frac{a}{b}) ^{c} = \frac{ {a}^{c} }{ {b}^{c} }$
We get this:
$\frac{{6}^{3} }{ {3}^{3} } = \frac{216}{27} = 8$

4 0

4 years ago

If 14 g of a radioactive substance are present initially and 3 yr later only 7 g remain, how much of the substance will be pres

marishachu [46]

It would be 48 bc if you add it all up and subtract it and add again and multiply and divide and multiply within a and the substance of present after 6 yr you will see that i have wasted your time and that is not the answer

5 0

3 years ago