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2 years ago

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tina, stacey, and amir were all born in july 4th. stacy is one year younger than tina. amir is 2 years older than tina. the prod

uct of all three of their ages is 2340.

1 answer:

MA_775_DIABLO [31]2 years ago

5 0

Answer:

2339

Step-by-step explanation:

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3 years ago

Write the equation of the line parallel to 3x - 4y = 18 that goes through<br> the point (8,-3)

kkurt [141]

Answer:

y=3/4x-9

Step-by-step explanation:

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2 years ago

What is the slope of the line that passes through (3, -4) and (-2, 5). A)-5/9 B)-9/5 C)9/5 D)5/9

alisha [4.7K]

M = (y2 - y1) / (x2 - x1)
Call (3,-4) one point
Call (-2,5) the second point.

m = (5- -4) / (-2 - 3)
m = 9/-5 = - 9 / 5

B<<<< answer

7 0

3 years ago

Find an antiderivative F(x) with F′(x) = f(x) = 6 + 24x^3 + 18x^5 and F(1)=0.

7nadin3 [17]

Answer:

The antiderivative is $F(X) = 6x + 6x^4 + 3x^6 - 15$ .

Step-by-step explanation:

Antiderivative F(x)

This is the integral of $F^{\prime}(x)$

So

F′(x) = f(x) = 6 + 24x^3 + 18x^5

Then:

$F(x) = \int (6 + 24x^3 + 18x^5) dx$

$F(x) = 6x + \frac{24x^4}{4} + \frac{18x^6}{6} + K$

$F(x) = 6x + 6x^4 + 3x^6 + K$

F(1)=0

$F(X) = 0$ when $x = 1$ . We use this to find K.

$F(x) = 6x + 6x^4 + 3x^6 + K$

$0 = 6 + 6 + 3 + K$

$K = -15$

Thus

The antiderivative is $F(X) = 6x + 6x^4 + 3x^6 - 15$ .

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2 years ago

Help<br> I’ll give a lot of credits

jenyasd209 [6]

Answer:

52.5

Step-by-step explanation:

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2 years ago