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SCORPION-xisa [38]
1 year ago
10

The population of a town in 2020 is 40% less than it was in 1980. Find the population in 1980 if it is 49,992 in 2020.

Mathematics
1 answer:
NNADVOKAT [17]1 year ago
3 0

The population of the town in 1982 is 29995.2.

<h3>What is a percentage?</h3>

A ratio or value that may be stated as a fraction of 100 is called a percentage. And it is represented by the symbol '%'.

Given, the population in 2020 is 49992.

40 percentage of population

= 40 % of 49992

= 40 x 49992/100

= 19996.8

Now the population in 1982

= population in 2020 - 40% of population in 1982

= 49992 - 19996.8

= 29995.2

Therefore the population in 1982 is 29995.2.

To learn more about the percentage;

brainly.com/question/24159063

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6 0
3 years ago
What is the length of the hypotenuse for a right triangle with legs of length 9 and 40? A) 41 B) 43 C) 45 D) 47
Katena32 [7]

Answer:

A) 41

Step-by-step explanation:

Let the hypotenuse be denoted by h

perpendicular as p and base as b

According to the Pythagoras theorem

h²=p²+b²

h =  \sqrt{ {p}^{2} +  {b}^{2}  }

h =   \sqrt{ {(40)}^{2}  +  {(9)}^{2} }

h =  \sqrt{1600 + 81}  =  \sqrt{1681}

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8 0
4 years ago
The distribution of resistance for resistors of a certain type is known to be normal, with 10% of all resistors having a resista
baherus [9]

Answer:

The mean is 9.65 ohms and the standard deviation is 0.2742 ohms.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

10% of all resistors having a resistance exceeding 10.634 ohms

This means that when X = 10.634, Z has a pvalue of 1-0.1 = 0.9. So when X = 10.634, Z = 1.28.

Z = \frac{X - \mu}{\sigma}

1.28 = \frac{10.634 - \mu}{\sigma}

10.634 - \mu = 1.28\sigma

\mu = 10.634 - 1.28\sigma

5% having a resistance smaller than 9.7565 ohms.

This means that when X = 9.7565, Z has a pvalue of 0.05. So when X = 9.7565, Z = -1.96.

Z = \frac{X - \mu}{\sigma}

-1.96 = \frac{9.7565 - \mu}{\sigma}

9.7565 - \mu = -1.96\sigma

\mu = 9.7565 + 1.96\sigma

We also have that:

\mu = 10.634 - 1.28\sigma

So

10.634 - 1.28\sigma = 9.7565 + 1.96\sigma

1.96\sigma + 1.28\sigma = 10.645 - 9.7565

3.24\sigma = 0.8885

\sigma = \frac{0.8885}{3.24}

\sigma = 0.2742

The mean is

\mu = 10.634 - 1.28\sigma = 10 - 1.28*0.2742 = 9.65

The mean is 9.65 ohms and the standard deviation is 0.2742 ohms.

8 0
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Which statement is true about the frequency distribution below
dexar [7]

Answer:

 

Step-by-step explanation:

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