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2 years ago

Help me plz i’ll give extra points

Mathematics

1 answer:

Anon25 [30]2 years ago

8 0

B,D

(1,3),(2,5),(3,7)(4,9)
(1,3),(2,3),3,3)(4,3)

I think that’s it

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Write an equation to find the amount of interest $450,000 earns in 1 year at a simple interest rate of 3.5%.

telo118 [61]

Answer:

The required equation for the amount of Simple Internet = $\frac{450,000 \times 1 \times 3.5}{100}$

Step-by-step explanation:

Here , Principal amount = $450,000

Time = 1 year

Rate of Interest = 3.5%

Now,SIMPLE INTEREST = $\frac{P \times R \times T}{100}$

So, here SI = $\frac{450,000 \times 1 \times 3.5}{100}$

Hence, the required equation for the amount of Simple Internet = $\frac{450,000 \times 1 \times 3.5}{100}$

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3 years ago

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What is the equation of the line?

inessss [21]

The answer would be x=-9

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2 years ago

Combine like terms fir the following expression: -3x+14-11+11x

babymother [125]

Answer:

8x + 3

Step-by-step explanation:

In the expression -3x + 14 - 11 + 11x, we have two pairs of like terms that can be combined together:

-3x, 11x

14, -11

If we rewrite this expression with the like terms together, it would look like this:

-3x+11x + 14-11

To make the addition of -3x and 11x easier, we could switch their places in the expression to make it look like this:

11x-3x + 14-11

(Note: Even though we are switching the terms' places, the -3x still keeps its negative sign when you move it around.

11x-3x is 8x and 14-11 is 3.

Therefore, the expression -3x + 14 - 11 + 11x can be simplified by combining like terms into 8x + 3.

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3 years ago

SAT scores (out of 1600) are distributed normally with a mean of 1100 and a standard deviation of 200. Suppose a school council

fgiga [73]

Answer:

0.91517

Step-by-step explanation:

Given that SAT scores (out of 1600) are distributed normally with a mean of 1100 and a standard deviation of 200. Suppose a school council awards a certificate of excellence to all students who score at least 1350 on the SAT, and suppose we pick one of the recognized students at random.

Let A - the event passing in SAT with atleast 1500

B - getting award i.e getting atleast 1350

Required probability = P(B/A)

= P(X>1500)/P(X>1350)

X is N (1100, 200)

Corresponding Z score = $\frac{x-1100}{200}$

$P(X>1500)/P(X>1350)\\= \frac{P(Z>2)}{P(Z>1.25} \\=\frac{0.89435}{0.97725} \\=0.91517$

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3 years ago

How do i do this- my brain has ✨evaporated✨

worty [1.4K]

Answer:

lol

Step-by-step explanation:

im not even sure try using google

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2 years ago