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3 years ago

Write the equation of the circle with center (−3, 2) and (6, 4) a point on the circle.

Mathematics

2 answers:

avanturin [10]3 years ago

6 0

Radius=sqrt(2^2+9^2)
r=9.22
equation
(x+3)^2+(y-2)^2=9.22^2
(x+3)^2+(y-2)^2=85

Leviafan [203]3 years ago

4 0

$(x-h)^2+(y-k)^2=r^2$
center is (h,k) and radius is r

so

given center=(-3,2)=(h,k)
$(x-(-3))^2+(y-2)^2=r^2$
$(x+3)^2+(y-2)^2=r^2$
find r^2
ok, (6,4) is a point
sub 6 for x and 4 for y and evaluate

$(6+3)^2+(4-2)^2=r^2$
$(9)^2+(2)^2=r^2$
$81+4=r^2$
$85=r^2$

the equation is
$(x+3)^2+(y-2)^2=85$

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For parabolas drawn like that in the picture, the general form is (x - h)² = +4a(y-k), where the vertex is (h,k) and a is the distance from the vertex to the focus. From the picture, the vertex is at (0,3). Then, we use point D(-2,4) to determine a:

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x² = 4(y - 3)
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Part B. Point D was already verified above. Now for point E(2,4)
x² = 4y - 12
2² ? 4(4) - 12
4 ? 4
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Part C. For y < 7x − 4, ignore the equality symbol first and graph the line. Assign random values of x, then you get corresponding values of y. Plot them as shown in the second picture. The line is shown in red. Next, test the equation by choosing a random point. Let's choose the purple point at (4,3).

3 ? 7(4) − 4
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3 years ago

42 is 30% of what number??? Add work plz

romanna [79]

X - the number

$30\% x =42 \\
\frac{30}{100}x=42 \\
\frac{3}{10}x=42 \\
x=42 \times \frac{10}{3} \\
x=\frac{420}{3} \\
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3 years ago

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blagie [28]

Partial products are the products obtained during the intermediate stages in order to complete a multiplication process.

Consider 68 $\times$ 43, we have to determine the partial products in this.

Now, $68 \times 43$

Expanding this, we get

$(60+8) \times (40+3)$

= $(60\times 40) +(60 \times 3) + (8 \times 40) + (8 \times 3)$

= 2400 + 180 + 320 + 24

= 2924

Hence, $8 \times 40=320$ and $8 \times 3 = 24$ are the required partial products in the product of 68 and 43.

So, Option 3 and 4 are the correct answers.

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