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Marrrta [24]
2 years ago
9

Write the improper fraction 31/20 as a mixed number?

Mathematics
1 answer:
sveta [45]2 years ago
7 0
\dfrac{31}{20}=\dfrac{20+11}{20}=\dfrac{20}{20}+\dfrac{11}{20}=1\dfrac{11}{20}
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Line HJ bisects BC at point H<br> BH = 5x - 1<br> and HC =4x + 3<br> Frd the length of BC
Levart [38]

Answer:

Step-by-step explanation:

5x - 1 = 4x + 3

x - 1 = 3

x = 4

5(4) - 1 + 4(4) + 3

20 - 1 + 16 + 3

19 + 16 + 3 = 35 + 3 = 38

8 0
3 years ago
Past experience has indicated that the breaking strength of yarn used in manufacturing drapery material is normally distributed
vlabodo [156]

Answer:

95% two-sided confidence interval on the true mean breaking strength is (94.8cm, 99.2cm)

Step-by-step explanation:

Our sample size is 11.

The first step to solve this problem is finding our degrees of freedom, that is, the sample size subtracted by 1. So

df = 11-1 = 10.

Then, we need to subtract one by the confidence level \alpha and divide by 2. So:

\frac{1-0.95}{2} = \frac{0.05}{2} = 0.025

Now, we need our answers from both steps above to find a value T in the t-distribution table. So, with 10 and 0.025 in the two-sided t-distribution table, we have T = 1.812

Now, we find the standard deviation of the sample. This is the division of the standard deviation by the square root of the sample size. So

s = \frac{4}{\sqrt{11}} = 1.2060

Now, we multiply T and s

M = Ts = 1.812*1.2060 = 2.19/tex]For the lower end of the interval, we subtract the sample mean by M. So the lower end of the interval here is[tex]L = 97 - 2.19 = 94.81 = 94.8cm

For the upper end of the interval, we add the sample mean and M. So the upper end of the interval here is

L = 97 + 2.19 = 99.19 = 99.2cm

So

95% two-sided confidence interval on the true mean breaking strength is (94.8cm, 99.2cm).

7 0
3 years ago
On average, 6 traffic accidents occur every 3 months at a certain intersection.
lions [1.4K]
The answer to this question is 2/3.
3 0
3 years ago
Find the GCF of the monomials: 32x^2 and 24x^2y
aev [14]

Answer:

8x^2

Explanation:

First, do prime factorization of each of the coefficients:

32   ⇒   2^5

24   ⇒   2^3, 3

The greatest common factor (GCF) of the coefficients is 2^3 = 8.

Next, find the GCF of the variables:

x^2

x^2, y

The GCF of the variables is x^2.

Finally, multiply the GCF of the coefficients by the GCF of the variables to get:

8x^2

4 0
1 year ago
Emilio writes the inequality 17(f+2)+45.99&lt;200 The situation using the variable as to represent the number of friends solve a
larisa [96]

Answer:

7 friends

Step-by-step explanation:

Given the inequality expression

17(g+2)+45.99<200

We are to find the value of g that satisfies the inequality

Expand

17g+34 +45.99<200

17g+79.99<200

Subtract 79.99 from both sides

17g+79.99-79.99<200-79.99

17g<120.01

g<120.01/17

g<7.059

Hence the max number of friend that can attend is 7friends.

7 0
3 years ago
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