Answer:
![\Sigma_{k=1}^{n}[3(\frac{10}{9} )^{k-1}]](https://tex.z-dn.net/?f=%5CSigma_%7Bk%3D1%7D%5E%7Bn%7D%5B3%28%5Cfrac%7B10%7D%7B9%7D%20%29%5E%7Bk-1%7D%5D)
Step-by-step explanation:
A geometric sequence is a list of numbers having a common ratio. Each term after the first is gotten by multiplying the previous one by the common ratio.
The first term is denoted by a and the common ratio is denoted by r.
A geometric sequence has the form:
a, ar, ar², ar³, . . .
The nth term of a geometric sequence is 
Therefore the sum of the first n terms is:

Given a geometric series with a first term of 3 and a common ratio of 10/9, the sum of the first n terms is:
Answer:
151
Step-by-step explanation:
Plug in 23(6)+5(3)-2
Simplify 138+15-2
Solve 153-2
151
Answer:
n = 6
Step-by-step explanation:
To isolate n, subtract 1 from both sides:
4n + 1 = 25
4n = 24
Then divide by 4 on both sides:
4n = 24
n = 6
Hope this helped :)
7 + 2x = 51
hope this helps
Answer:
C
Step-by-step explanation:
● 2.4 × 10^5
10^5 is 100000
● 2.4 × 100000
● 240 000