Can someone help please?

Mathematics

2 answers:

ArbitrLikvidat [17]3 years ago

6 0

Y-int: is positive 4.
Slope: is 2/1x which is also 2x.
The equation: is 2x+4.
If it’s wrong I apologize, I haven’t done this in a while I’m sure it’s correct tho.
I hope this helped.

olga nikolaevna [1]3 years ago

5 0

Step-by-step explanation:

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9) Farmer Joe has lots of rabbits and lots of predators on his farm. Only 3 out of every 10 rabbits live

qaws [65]

<h2>Answer: 90 rabbits</h2>

<h3>Step-by-step explanation:</h3>

you will need 10 for every 3 rabbits so if you count in tens and three's

3=10

6=20

9=30

and so on..

when you get to 27 you'll be at 90

27=90

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8 0

2 years ago

Alex wants to fence in an area for a dog park. He has plotted three sides of the fenced area at the points E (1, 5), F (3, 5), a

hram777 [196]

Answer:

$(1,1)$

Step-by-step explanation:

Given: E, F, G, H denote the three coordinates of the area fenced

To find: coordinates of point H

Solution:

According to distance formula,

length of side joining points $(x_1,y_1)\,,\,(x_2,y_2)$ is equal to $\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

So,

$EF=\sqrt{(3-1)^2+(5-5)^2}=2\,\,units\\FG=\sqrt{(6-3)^2+(1-5)^2}=\sqrt{9+16}=5\,\,units\\GH=\sqrt{(x-6)^2+(y-1)^2}\\EH=\sqrt{(x-1)^2+(y-5)^2}$

Perimeter of a figure is the length of its outline.

$EF+FG+GH+EH=16\\2+5+\sqrt{(x-6)^2+(y-1)^2}+\sqrt{(x-1)^2+(y-5)^2}=16\\\sqrt{(x-6)^2+(y-1)^2}+\sqrt{(x-1)^2+(y-5)^2}=16-2-5\\\sqrt{(x-6)^2+(y-1)^2}+\sqrt{(x-1)^2+(y-5)^2}=9$