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Margaret [11]
3 years ago
13

Help me out plzzzzzzzzzz!

Mathematics
1 answer:
valentinak56 [21]3 years ago
4 0

Answer:

  1. Independent: one event doesn't depend on the other.
  2. P(Even|Tails): 3/6×1/2= 3/12= 1/4
  3. 0.25 --> 25%
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How do i solve for y and z?
MAVERICK [17]
Y = 6, z = 2

~Hope this helped!~

(The first page is the beginning of the equation, and the next page is the ending)

5 0
3 years ago
3,15,75,375 9th term
e-lub [12.9K]

Answer:

1,171,875

Step-by-step explanation:

The sequence is multiplying by 5 every time. It will be 3, 15, 75, 375, 1875, 9375, 46,875, 234,375, and then 1,171,875

5 0
3 years ago
Assume that you have a sample of n 1 equals 6​, with the sample mean Upper X overbar 1 equals 50​, and a sample standard deviati
tigry1 [53]

Answer:

t=\frac{(50 -38)-(0)}{7.46\sqrt{\frac{1}{6}+\frac{1}{5}}}=2.656

df=6+5-2=9

p_v =P(t_{9}>2.656) =0.0131

Since the p value is higher than the significance level given of 0.01 we don't have enough evidence to conclude that the true mean for group 1 is significantly higher thn the true mean for the group 2.

Step-by-step explanation:

Data given

n_1 =6 represent the sample size for group 1

n_2 =5 represent the sample size for group 2

\bar X_1 =50 represent the sample mean for the group 1

\bar X_2 =38 represent the sample mean for the group 2

s_1=7 represent the sample standard deviation for group 1

s_2=8 represent the sample standard deviation for group 2

System of hypothesis

The system of hypothesis on this case are:

Null hypothesis: \mu_1 \leq \mu_2

Alternative hypothesis: \mu_1 > \mu_2

We are assuming that the population variances for each group are the same

\sigma^2_1 =\sigma^2_2 =\sigma^2

The statistic for this case is given by:

t=\frac{(\bar X_1 -\bar X_2)-(\mu_{1}-\mu_2)}{S_p\sqrt{\frac{1}{n_1}+\frac{1}{n_2}}}

The pooled variance is:

S^2_p =\frac{(n_1-1)S^2_1 +(n_2 -1)S^2_2}{n_1 +n_2 -2}

We can find the pooled variance:

S^2_p =\frac{(6-1)(7)^2 +(5 -1)(8)^2}{6 +5 -2}=55.67

And the pooled deviation is:

S_p=7.46

The statistic is given by:

t=\frac{(50 -38)-(0)}{7.46\sqrt{\frac{1}{6}+\frac{1}{5}}}=2.656

The degrees of freedom are given by:

df=6+5-2=9

The p value is given by:

p_v =P(t_{9}>2.656) =0.0131

Since the p value is higher than the significance level given of 0.01 we don't have enough evidence to conclude that the true mean for group 1 is significantly higher thn the true mean for the group 2.

4 0
3 years ago
What it 17.15 in 12hour clock
Marrrta [24]

Answer:

Step-by-step explanation:

Hello friend

The answer is 5:15 in 12 hour clock

8 0
3 years ago
Read 2 more answers
How many degress are in an angle that cuts 2/4 of a circle
saw5 [17]
B:180 degrees because a circle is 360 degrees and half of 360 is 180. I'm learning this too lol
4 0
3 years ago
Read 2 more answers
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