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rosijanka [135]
3 years ago
9

F(x)=1.01(2)x rate of change from x=12 to x=15

Mathematics
1 answer:
laiz [17]3 years ago
5 0
6.06
because 1.01 times 2 times 12 is 24.24
and 1.01 times 2 times 15 is 30
30- 24.24 is 6.06
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F(x)= x +4<br> g(x) = 3x<br> Work out the value of gf (5).
MrMuchimi

The value of gf(5) for the given two expressions is 135.

According to the question,

We have the following information:

f(x)= x +4

g(x) = 3x

Now, in order to find the value of gf(5), we will first find the value of gf.

Now, we will multiply these two expressions:

3x(x+4)

Now, the terms outside the brackets need to multiplied inside the bracket:

3x^{2} +12x

Now, we will put the value of x in this expression as 5 and solve the expression further by multiplication and addition:

3*5*5+12*5

75+60

135

Hence, the value of gf(5) for the given two expressions of f(x) and g(x) is 135.

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1 year ago
A submarine was located 200 feet below sea level. If it ascends 55 feet and then drops 87 feet, then which integer represents th
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Answer:

-232

Step-by-step explanation:

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3 years ago
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Combine like terms 3x^2 + 4x^3 + 6x^2
ololo11 [35]
9x^2 + 4x^3
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3 years ago
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PLEASE HELP, I REALLY NEED IT!!!
kogti [31]

The number which is express in each of the models as given in the image attached to the task content are as follows;

a). 1.37

b). 1.37

c). 1.37.

<h3>What numbers are expressed according to the given models in the task content?</h3>

It follows from the task content that the models describe that One flat represents 1 whole, One rod represents 1 tenth and one unit represents 1 hundredth.

It therefore follows from the task content that in each of the models, the algebraic sum of flat(s), rods and units as the case may be results in the value; 1.37 as the utmost number represented by the models.

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2 years ago
A race car was attempting to set a record the race car went 1000 feet in 4.5 seconds to the nearest Tenth what is the average sp
V125BC [204]

Answer:

222 ft/sec

Step-by-step explanation:

Essentially you're being asked to find the unit speed (that is, distance per sec).

1000 ft

------------ = 222 feet/sec is the approx. average speed / unit speed

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