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ratelena [41]
3 years ago
13

Devon purchased tickets to an air show for 9 adults and 2

Mathematics
2 answers:
Vladimir79 [104]3 years ago
6 0

Answer:

18$ per adult, 15 per clild

Step-by-step explanation:

Brainly plzzzz

Novay_Z [31]3 years ago
3 0

Answer:

An adults ticket would be $18 and a child's ticket would be $15

Step-by-step explanation:

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A teacher writes a simple computer program where she can type students name and computer tells her the students birthday.
Vikki [24]

Considering that each student has only one birthday, each input will be related to only one output, hence this relation is a function.

<h3>When does a relation represent a function?</h3>

A relation represents a function when each value of the input is mapped to only one value of the output.

For this problem, we have that:

  • The input is the student's name.
  • The output is the student's birthday.

Each student has only one birthday, hence each input will be related to only one output, hence this relation is a function.

More can be learned about relations and functions at brainly.com/question/12463448

#SPJ1

5 0
1 year ago
~**Will mark brainliest **~<br> For the correct answers to all three questions
aleksandr82 [10.1K]

a)

\dfrac{42}{65}\cdot\dfrac{25}{36}\cdot\dfrac{26}{49}=\dfrac{2\cdot3\cdot7}{5\cdot13}\cdot\dfrac{5\cdot5}{2\cdot2\cdot3\cdot3}\cdot\dfrac{2\cdot13}{7\cdot7}=\dfrac{7}{13}\cdot\dfrac{5}{2\cdot3}\cdot\dfrac{2\cdot13}{7\cdot7}=\\\\\\=\dfrac{1}{1}\cdot\dfrac{5}{2\cdot3}\cdot\dfrac{2}{7}=\dfrac{5}{3}\cdot\dfrac{1}{7}=\dfrac{5}{21}

b)

\dfrac{21}{32}\cdot\dfrac{39}{120}\cdot\dfrac{40}{65}=\dfrac{21}{32}\cdot\dfrac{3\cdot13}{2\cdot2\cdot2\cdot3\cdot5}\cdot\dfrac{2\cdot2\cdot2\cdot5}{5\cdot13}=\\\\\\=\dfrac{3\cdot7}{32}\cdot\dfrac{13}{2\cdot2\cdot2\cdot5}\cdot\dfrac{2\cdot2\cdot2}{13}=\dfrac{21}{32}\cdot\dfrac{1}{5}\cdot\dfrac{1}{1}=\dfrac{21}{160}

c)

\dfrac{15}{90}\cdot\dfrac{36}{75}\cdot\dfrac{27}{42}=\dfrac{3\cdot5}{2\cdot3\cdot3\cdot5}\cdot\dfrac{2\cdot2\cdot3\cdot3}{3\cdot5\cdot5}\cdot\dfrac{3\cdot3\cdot3}{2\cdot3\cdot7}=\\\\\\=\dfrac{1}{2\cdot3}\cdot\dfrac{2\cdot2\cdot3}{5\cdot5}\cdot\dfrac{3\cdot3}{2\cdot7}=\dfrac{1}{1}\cdot\dfrac{2}{5\cdot5}\cdot\dfrac{3\cdot3}{2\cdot7}=\dfrac{1}{25}\cdot\dfrac{9}{7}=\dfrac{9}{175}

6 0
3 years ago
A fundamental basis of regression analysis is the assumption of a. the lack of a relationship between independent variables. b.
kodGreya [7K]

The correct answer is E. A fundamental basis of regression analysis is the assumption of the existence of two independent variables for every dependent variable.

Regression analysis is a statistical method that examines the dependence of a response variable on selected explanatory variables.

When studying the dependence between quantities and trying to describe a given functional dependence on a given formula, it is assumed that the dependence consists of a precisely determinable component and a random component. The relationship with this assumption is called the regression model.

Learn more about regression analysis in brainly.com/question/1305938

5 0
2 years ago
B. Translate each word into algebraic eqaution. (Use any letter)
Ymorist [56]
For 1

Twice a number means
A number used two times
Is that number was x
What do we do to x
8 0
2 years ago
Suppose a certain character in a role-playing game has an ability to use in battles. When activated, the ability deals damage to
Helen [10]

Answer:

The chance of getting exactly 3 hits is =  0.20

Step-by-step explanation:

P.S - The exact question is -

As given,

F(x) = 0 ,          x < 1

         0.30 ,     1  ≤ x < 2

         0.56 ,     2 ≤ x < 3

         0.76 ,     3 ≤ x < 4

         0.9 ,       4  ≤ x < 5

         1 ,            5  ≤ x

Now,

f(x) = 0.30 ,                            x = 1

        0.56 - 0.30 = 0.26 ,     x = 2

         0.76 - 0.56 = 0.20 ,     x=3

         0.9 - 0.76 = 0.14  ,       x = 4

         1 - 0.9 = 0.1 ,                 x = 5

          0,                                 otherwise

Now,

The chance of getting exactly 3 hits is = f(x = 3) = 0.20

8 0
3 years ago
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