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Flura [38]
3 years ago
14

Mrs. Brown uses

Mathematics
1 answer:
Harrizon [31]3 years ago
3 0

Answer:

6

Step-by-step explain

1.5 divide by .25 = 6

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Need help with this asap
Katarina [22]

There is no relationship between the number of hours cycled and the number of hours worked (Option D).

<h3>What is a scatterplot?</h3>

A scatterplot is a graph that is used to show the association between two variables. The relationship between the variables is shown by the use of  line of best fit.

From the scatterplot shown, we can conclude that there is no relationship between the number of hours cycled and the number of hours worked (Option D).

Learn more about scatterplot:brainly.com/question/25280625

#SPJ1

7 0
2 years ago
Don't skip this I need help!
Anvisha [2.4K]
0.50c, as it's $0.50 per cup and c represents the number of cups sold. When you have a variable (letter like in this case, which is c) you always multiply.

And for 1b you're going to be doing $127.50 divided by $0.50 

Let me know if this makes sense
6 0
4 years ago
Is 47.2 greater than 47.197?​
DaniilM [7]
Yes. Since neither are rounded, 46.2 would be greater.
7 0
1 year ago
Read 2 more answers
The random variable x is the number of occurrences of an event over an interval of ten minutes. It can be assumed that the proba
mart [117]

Answer:

The probablility that there are 8 occurrences in ten minutes is 0.00518 or 0.5%.

Step-by-step explanation:

The distribution that represents the ocurrence of this events is the Poisson distribution.

The probability of having k events in a ten-minute-period can be expressed as:

P(x=k)=\frac{ \lambda^ke^{-k}}{k!}

being λ the mean number of occurrences in ten minutes.

The probablility that there are 8 occurrences in ten minutes can be calculated as:

P(x=k)=\frac{ \lambda^ke^{-k}}{k!}\\\\P(x=8)=\frac{5.3^8e^{-8}}{8!}=\frac{(622596*0.000335463)}{40320}=0.00518

The probablility that there are 8 occurrences in ten minutes is 0.00518 or 0.5%.

5 0
3 years ago
A customer service phone line claims that the wait times before a call is answered by a service representative is less than 3.3
8_murik_8 [283]

Answer:

Step-by-step explanation:

Let x be the wait times before a call is answered in phone calls.

The claim is x bar <3.3 minutes

Sample size n =62

Sample mean - x bar = 3.24 minutes

Population std dev =\sigma = 0.40 minutes\\

Since population std dev is known and also sample size is sufficiently large, we can use Z test.

H_0: x bar = 3.3\\H_a: x bar

(one tailed test)

Mean difference = 3.24-3.3 = -0.06 min

Std error of sample =\frac{\sigma}{\sqrt{n} } =\frac{0.40}{\sqrt{62} } \\=0.0508

Z = tset statistic = \frac{-006}{0.0508} \\\\=-1.18

p value = 0.119

Since p value > alpha, we accept null hypothesis.

There is no evidence to support the claim at alpha = 0.08

3 0
3 years ago
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