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Aloiza [94]
3 years ago
13

A camp needs 100 students to help with the 4-year old campers. Eight students from 4 different classes have agreed to help. How

many more students are needed? Show your work.​
Mathematics
1 answer:
vladimir2022 [97]3 years ago
8 0

Answer:

68

Step-by-step explanation:

First you multiply 8 and 4 to get 32 and that shows you how many campers have agreed to help. Next you have to subtract 32 from 100 to know how many more people you need.

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The model of a shopping mall is made using a scale of 1: 50
jekas [21]

Answer:

20 m

Step-by-step explanation:

Given that :

Scale of 1 : 50 is used to make a model

If the model has a height of 40 cm ; the height of the house is:

Then, the actual height of the house is (40 * 50) = 2000 cm

Thus the height of the house in metre is :

100cm = 1 meter

2000 cm = 2000 / 100

2000 cm = 20 meter

Height of house in meter = 20 meter

3 0
3 years ago
What two numbers add to 7 and multiply to 0??
ANTONII [103]
Anything times 0 is zero. 
What number plus zero is equal to 7? 7. 

Two numbers that add to 7 and multiply to 0 are 0 and 7. 

0 x 7 = 0
0 + 7 = 7
5 0
3 years ago
Read 2 more answers
Write the equation -4x^2+9y^2+32x+36y-64=0 in standard form. Please show me each step of the process!
IgorC [24]
Hey there, hope I can help!

-4x^2+9y^2+32x+36y-64=0

\mathrm{Add\:}64\mathrm{\:to\:both\:sides} \ \textgreater \  9y^2+32x+36y-4x^2=64

\mathrm{Factor\:out\:coefficient\:of\:square\:terms} \ \textgreater \  -4\left(x^2-8x\right)+9\left(y^2+4y\right)=64

\mathrm{Divide\:by\:coefficient\:of\:square\:terms:\:}4
-\left(x^2-8x\right)+\frac{9}{4}\left(y^2+4y\right)=16

\mathrm{Divide\:by\:coefficient\:of\:square\:terms:\:}9
-\frac{1}{9}\left(x^2-8x\right)+\frac{1}{4}\left(y^2+4y\right)=\frac{16}{9}

\mathrm{Convert}\:x\:\mathrm{to\:square\:form}
-\frac{1}{9}\left(x^2-8x+16\right)+\frac{1}{4}\left(y^2+4y\right)=\frac{16}{9}-\frac{1}{9}\left(16\right)

\mathrm{Convert\:to\:square\:form}
-\frac{1}{9}\left(x-4\right)^2+\frac{1}{4}\left(y^2+4y\right)=\frac{16}{9}-\frac{1}{9}\left(16\right)

\mathrm{Convert}\:y\:\mathrm{to\:square\:form}
-\frac{1}{9}\left(x-4\right)^2+\frac{1}{4}\left(y^2+4y+4\right)=\frac{16}{9}-\frac{1}{9}\left(16\right)+\frac{1}{4}\left(4\right)

\mathrm{Convert\:to\:square\:form}
-\frac{1}{9}\left(x-4\right)^2+\frac{1}{4}\left(y+2\right)^2=\frac{16}{9}-\frac{1}{9}\left(16\right)+\frac{1}{4}\left(4\right)

\mathrm{Refine\:}\frac{16}{9}-\frac{1}{9}\left(16\right)+\frac{1}{4}\left(4\right) \ \textgreater \  -\frac{1}{9}\left(x-4\right)^2+\frac{1}{4}\left(y+2\right)^2=1

Refine\;once\;more\;-\frac{\left(x-4\right)^2}{9}+\frac{\left(y+2\right)^2}{4}=1

For me I used
\frac{\left(y-k\right)^2}{a^2}-\frac{\left(x-h\right)^2}{b^2}= 1
As\;\mathrm{it\;\:is\:the\:standard\:equation\:for\:an\:up-down\:facing\:hyperbola}

I know yours is an equation which is why I did not go any further because this is the standard form you are looking for. I would rewrite mine to get my hyperbola standard form. However the one I have provided is the form you need where mine would be.
\frac{\left(y-\left(-2\right)\right)^2}{2^2}-\frac{\left(x-4\right)^2}{3^2}=1

Hope this helps!
4 0
3 years ago
Heather has $45.71 in her savings account. She bought six packs of markers to donate to her school. If each pack of markers cost
Fittoniya [83]
The answer would be D. $21.77
4 0
3 years ago
Read 2 more answers
1.) (-18, -20) (18, 16)
aleksandrvk [35]

1.) (-18, -20) (18, 16)

m= 1

2.) (-7, 14) (-11, 4)

m= 5/2

3.) (-5, -4) (3, 9)

m= 13/8

4.) (13, -8) (-9, -1)

m= -7/22

3 0
3 years ago
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