If you would like to calculate the arithmetic mean, geometric mean, and harmonic mean from the following averages, you can calculate this using the following steps:
averages: 56.4, 59.8, 55.8
the number of values: 3
arithmetic mean:
(56.4 + 59.8 + 55.8) / 3 = 57.33
geometric mean:
(56.4 * 59.8 * 55.8)^(1/3) = 57.31
harmonic mean:
3 / (1/56.4 + 1/59.8 + 1/55.8) = 57.28
Looks like all you have to do it multiply the numbers together; there is no application of the Distributive Property to these problems.
1.) y+6=3(x+2) C
y+6=3x+6
y=3x+6-6
y=3x+6
2.) y=1/2(x+8)-2 B
y=1/2x+4-2
y=1/2x+2
3.) y+1=1(x-3) E
y+1=x-3
y=x-3-1
y=x-4
4.) -4x+y=-2 A
y=-4x-2
5.) 2x-4y=-4 F
-4y=-2x-4
y=-2/-4x-4/-4
y=2/4x+4/4
y=1/2x+1
6.) 2x+4y=8 D
4y=-2x+8
y=-2/4x+8/4
y=-1/2x+4/2
y=-1/2x+2
The probability that all of them will be defective is 0.0000759375
<em><u>Explanation</u></em>
The general <u>Binomial Probability</u> formula is....
, where p is the probability of success, n is the total number of trials and r is the desired numbers of trials.
Given, the probability that a computer will be defective is 0.15 , so p = 0.15
Five computers are manufactured and we need to find the probability that all of them will be defective. That means, n = 5 and r = 5
Now according to the above formula....
So, the probability that all of them will be defective is 0.0000759375
