3 years ago

How many solutions does the system of equations below have? Y=-x-3 2y+2x=-6

1 answer:

5 0

You can tell that there is only 1 solution because it is a linear system of equations. If you are not convinced, work it out yourself. :)

Hope this helps

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Eliminate the parameter,t, in the parametric equation, x=6cos t, and y =3 sin t

german

X = 6 cos(t)
y = 3 sin(t)

we can rewrite these equations as:

$\frac{x}{6}=cost(t) \\ \\ \frac{y}{3} =sin(t)$

Taking squares of both equations we get:

$( \frac{x}{6})^{2}=sin^{2} (t) \\ \\ 
( \frac{y}{3})^{2}=cos^{2}(t)$

Adding both the equations, we get:

$\frac{ x^{2} }{36}+ \frac{ x^{2} }{9}=sin^{2}(t)+cos^{2}(t) \\ \\ 
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yawa3891 [41]

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I hope it helps! If it does please mark me as a brainliest!

Step-by-step explanation:

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3 years ago

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fiasKO [112]

Answer:

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Since f(x) is graphed, you need to look at the specified intervals and see which of them have the entire portion graphed below the x axis.

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