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3 years ago

How many solutions does the system of equations below have? Y=-x-3 2y+2x=-6

Mathematics

1 answer:

adell [148]3 years ago

5 0

You can tell that there is only 1 solution because it is a linear system of equations. If you are not convinced, work it out yourself. :)

Hope this helps

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Which number like inequality represents n<-1?

Alenkinab [10]

The second one is your answer

7 0

2 years ago

A. {0,1,2,3,4}<br> B. {1,2,3,4}<br> C. {-1,0,1,2,3}<br> D. {-2,-1,0,1,2,3,4}

Harlamova29_29 [7]

Option D:

The set is {-2, -1, 0, 1, 2, 3, 4}.

Solution:

Given set:

$\{x \in Z:-2 \leq x \leq 4\}$

Z means integer values.

Integer means set of positive and negative values including zero.

$-2 \leq x \leq 4$

This means x lies between -2 and 4.

If x strictly less than -2 and greater than 4 means you don't have to include -2 and 4.
But here x less than or equal to -2 and greater than or equal to 4, so you have to include -2 and 4.

The integers are -2, -1, 0, 1, 2, 3 and 4.

So, x belongs to the set {-2, -1, 0, 1, 2, 3, 4}

Hence the given set is defined by the set {-2, -1, 0, 1, 2, 3, 4}.

Option D is the correct answer.

6 0

3 years ago

Any 10th grader solve it <br>for 50 points

kkurt [141]

Answer:

$\frac{a}{p}\times (q-r)+\frac{b}{q}\times (r-p)+\frac{c}{r}\times (p-q)\neq 0$ is proved for the sum of pth, qth and rth terms of an arithmetic progression are a, b,and c respectively.

Step-by-step explanation:

Given that the sum of pth, qth and rth terms of an arithmetic progression are a, b and c respectively.

First term of given arithmetic progression is A

and common difference is D

ie., $a_{1}=A$ and common difference=D

The nth term can be written as

$a_{n}=A+(n-1)D$

pth term of given arithmetic progression is a

$a_{p}=A+(p-1)D=a$

qth term of given arithmetic progression is b

$a_{q}=A+(q-1)D=b$ and

rth term of given arithmetic progression is c

$a_{r}=A+(r-1)D=c$

We have to prove that

$\frac{a}{p}\times (q-r)+\frac{b}{q}\times (r-p)+\frac{c}{r}\times (p-q)=0$

Now to prove LHS=RHS

Now take LHS

$\frac{a}{p}\times (q-r)+\frac{b}{q}\times (r-p)+\frac{c}{r}\times (p-q)$

$=\frac{A+(p-1)D}{p}\times (q-r)+\frac{A+(q-1)D}{q}\times (r-p)+\frac{A+(r-1)D}{r}\times (p-q)$

$=\frac{A+pD-D}{p}\times (q-r)+\frac{A+qD-D}{q}\times (r-p)+\frac{A+rD-D}{r}\times (p-q)$

$=\frac{Aq+pqD-Dq-Ar-prD+rD}{p}+\frac{Ar+rqD-Dr-Ap-pqD+pD}{q}+\frac{Ap+prD-Dp-Aq-qrD+qD}{r}$

$=\frac{[Aq+pqD-Dq-Ar-prD+rD]\times qr+[Ar+rqD-Dr-Ap-pqD+pD]\times pr+[Ap+prD-Dp-Aq-qrD+qD]\times pq}{pqr}$

$=\frac{Arq^{2}+pq^{2} rD-Dq^{2} r-Aqr^{2}-pqr^{2} D+qr^{2} D+Apr^{2}+pr^{2} qD-pDr^{2} -Ap^{2}r-p^{2} rqD+p^{2} rD+Ap^{2} q+p^{2} qrD-Dp^{2} q-Aq^{2} p-q^{2} prD+q^{2}pD}{pqr}$