Answer:
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r3jrpo3jr23
r3r
2r2
Step-by-step explanation:
3rn3u 4 i8jh34i j4i j40jr0 9j 4j 9043jt44j4542
<em>The </em><em>vertex of the function is at (5, 10)</em>
<em>For the function, th</em><em>e domain exists </em><em>on all </em><em>real numbers</em><em> while the range exist for the value</em><em> f(x) ≥ 10</em>
<h3>Vertex, domain and range of a function</h3>
The vertex of a quadratic or linear function is in the form
y = a(x – h)^2 + k
where;
(h, k) is the vertex of the function
Given the function expressed as;
f(x) = |x-5| + 10
On comparison, you can see that h = 5 and k =10, hence the vertex of the function is at (5, 10)
<u>For the domain and range</u>
Domain are the dependent variable for which a function exist while the range is the independent variable for which a function exist.
For the function, the domain exists on all real numbers while the range exist for the value f(x) ≥ 10
Learn more on vertex, domain and range here: brainly.com/question/544653
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Answer:
Step-by-step explanation:
3.1.1 What do you mean by SARS
Answer 3.1.2
20% of R190 = R38
38*500=R19000
The solution is x=5/4.
We use the properties of logs to rewrite the equation:
![\log[(\frac{x}{2})(\frac{20}{x^2})]=\log8 \\ \\\log(\frac{20x}{2x^2})=\log8 \\ \\\log(\frac{10}{x})=\log8](https://tex.z-dn.net/?f=%5Clog%5B%28%5Cfrac%7Bx%7D%7B2%7D%29%28%5Cfrac%7B20%7D%7Bx%5E2%7D%29%5D%3D%5Clog8%0A%5C%5C%0A%5C%5C%5Clog%28%5Cfrac%7B20x%7D%7B2x%5E2%7D%29%3D%5Clog8%0A%5C%5C%0A%5C%5C%5Clog%28%5Cfrac%7B10%7D%7Bx%7D%29%3D%5Clog8)
Get all of the logs on the same side of the equation y subtracting log 8:

Use the properties of logs to rewrite:

Exponentiate:

Multiply both sides by 8x:
1*8x = (10/8x)*8x
8x=10
Divide both sides by 8:
8x/8 = 10/8
x = 10/8 = 5/4