Try substituting those values, and you will see they do not fit either equation.
looking at the 2nd equation, y = x+2, so
x+2 = x^2+5x-3
x^2 + 4x - 5 = 0
(x+5)(x-1) = 0
x = -5 or 1
so, y = -3 or 3
the solutions are thus (-5,-3)(1,3)
Hope this helps
Please give me Brainliest
The zeros are (x+4)(x-4)(x+6)(x-3).
Answer: 28
Step-by-step explanation: you have to add 21 + 7 because your counting up from -7 to 21
Answer:
It would be the first one or second one
Step-by-step explanation:
the answer is up ahead
