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-Dominant- [34]
3 years ago
7

if a school library has 86 fiction books and 74 nonfiction books, what is the percentage of nonfiction books?

Mathematics
1 answer:
hodyreva [135]3 years ago
3 0

Answer:

46.25%

Step-by-step explanation:

First, add both numbers together. (86 + 74).

Next, we have 160. And that is 100%.

Now, we have to find what 74 is compared to 160.

74 is 46.25% of 160.

There's our answer.

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F(x)=3x-2
Yuri [45]

3x + 2 - 2
3x
When you distrubute the 3 in the parenthesis it will cancel out the fraction and make it a 2 because 6 divided by 3 is 2
Then you will have to subtract 2-2 and get 0 and you answer will be 3x

If you are wondering where i got the 6, 3/1 times 2/3 will equal 6/3
5 0
3 years ago
A rabbit population doubles every 6 weeks. There are currently 9 rabbits in a restricted area. If represents the time, in weeks,
Hatshy [7]

Oof actually IDK the answer. I can't figure it out. I got the answer 1,344 but I'm sure that's not right. I'm so sorry! :(

8 0
3 years ago
Given A= <br> What is the value of matrix B if A + B = C
tangare [24]

Answer:

A

Step-by-step explanation:

We know that 8+3x= x

solve for x

8= -2x

-4 =x

The only answer that has -4 is A

6 0
3 years ago
There are 3 types of gummy bears:
mr Goodwill [35]

Using proportions, it is found that it takes 886 more mini-bears than regular-bears to have the same weight as one super-bear.

<h3>What is a proportion?</h3>

A proportion is a fraction of a total amount, and the measures are related using a rule of three. Due to this, relations between variables, either direct(when both increase or both decrease) or inverse proportional(when one increases and the other decreases, or vice versa), can be built to find the desired measures in the problem, or equations to find these measures.

10 mini-bears weights to 12.1 grams, hence the weight of a mini-bear is of:

12.1/10 = 1.21 grams.

10 regular bears weights to 23.1 grams, hence the weight of a regular bear is of:

23.1/10 = 2.31 grams.

1 super bear weights to 2250 grams, hence the proportion between the <u>weight of a super bear and the weight of a mini-bear</u> is:

2250/1.21 = 1860.

The proportion between the <u>weight of a super bear and the weight of a regular bear</u> is:

2250/2.31 = 974.

The difference of proportions is given by:

1860 - 974 = 886.

It takes 886 more mini-bears than regular-bears to have the same weight as one super-bear.

More can be learned about proportions at brainly.com/question/24372153

#SPJ1

5 0
1 year ago
For the region bounded by y=2x​, the​ x-axis, and x=1​, determine which of the following is​ greater: the volume of the solid ge
telo118 [61]

Answer:

The correct answer B) The volumes are equal.

Step-by-step explanation:

The area of a disk of revolution at any x about the x- axis is πy² where y=2x. If we integrate this area on the given range of values of x from x=0 to x=1 , we will get the volume of revolution about the x-axis, which here equals,

\int\limits^1_0 {(pi)y^{2} } \, dx

which when evaluated gives 4pi/3.

Now we have to calculate the volume of revolution about the y-axis. For that we have to first see by drawing the diagram that the area of the CD like disk centered about the y-axis for any y, as we rotate the triangular area given in the question would be pi - pi*x². if we integrate this area over the range of value of y that is from y=0 to y=2 , we will obtain the volume of revolution about the y-axis, which is given by,

\int\limits^2_0 {pi - pix^{2} } \, dy = \int\limits^2_0 {1 - y^{2}/4 } \, dy

If we just evaluate the integral as usual we will get 4pi/3 again(In the second step i have just replaced x with y/2 as given by the equation of the line), which is the same answer we got for the volume of revolution about the x-axis. Which means that the answer B) is correct.

7 0
3 years ago
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