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2 years ago

Is 4n-2 equivalent to 2(n-1)

Mathematics

2 answers:

noname [10]2 years ago

7 0

No, when you do 4n-2 it equals to 2(2n-1) not 2(n-1)

8_murik_8 [283]2 years ago

4 0

Answer:

Step-by-step explanation:

For example: 4(2)-2 and 2(2-1)

6 is not equal to 2

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A box contains three plain pencils and 5 pens. A second box contains three colored pencils and three crayons. One item from each

worty [1.4K]

Answer:

Therefore the probability that a pen from the first box and a crayon from the second box are selected is $\frac5{16}$

Step-by-step explanation:

Probability:

The ratio of the number of favorable outcomes to the number all possible outcomes of the event.

$Probability=\frac{\textrm{The number favorable outcomes}}{\textrm{The number all possible}}$

Given that,

Three plain pencils and 5 pens are contained by the first box.

Total number of pens and pencils is =(3+5)=8

The probability that a pen is selected from the first box is

=P(A)

$=\frac{\textrm{The number pens}}{\textrm{Total number of pens and pencils}}$

$=\frac{5}{8}$

A second box contains three colored pencils and three crayons.

Total number of pencils and crayons is =(3+3)=6

The probability that a crayon is selected from the second box is

=P(B)

$=\frac{\textrm{The number of crayon}}{\textrm{Total number of crayons and pencils}}$

$=\frac{3}{6}$

Since both events are mutually independent.

The required probability is multiple of the events

Therefore the required probability is

$=\frac58\times \frac36$

$=\frac5{16}$

4 0

3 years ago

Its so easy Whats 1 + 1 = ?

Anika [276]

Answer:

1+1=2....................

4 0

2 years ago

Read 2 more answers

A local gym instructor has a course load that allows her to teach eight classes. At an interest meeting, 8 people wanted high-‐

cricket20 [7]

Answer:

The final curse load of the local gym instructor is this:

High-‐impact aerobics = 1

Low-‐impact aerobics = 4

Jazzercise = 1

Step exercise = 2

Step-by-step explanation:

1. Let's apportion the class load using the Hamilton method

Number of classes the local gym instructor can teach = 8

Total number of students that want to take a class = 114 (8 people wanted high-‐impact aerobics, 64 wanted low-‐impact aerobics, 11 wanted jazzercise, and 31 wanted step exercise)

Standard divisor = 114/8 = 14.25

Now, we can apportion the students in in Standard quotas, this way:

High-‐impact aerobics = 8/14.25 = 0.5614

Low-‐impact aerobics = 64/14.25 = 4.49

Jazzercise = 11/14.25 = 0.7719

Step exercise = 31/14.25 = 2.1754

Now, we find the Minimum quota, just considering the whole number and don't taking into account the decimals, this way:

High-‐impact aerobics = 0

Low-‐impact aerobics = 4

Jazzercise = 0

Step exercise = 2

As we can see we have 6 classes and there are 2 still pending. Those 2 goes to the classes with the highest decimal portion, in this case, Jazzercise .7719 and High-‐impact aerobics with .5614.

The final course load is this:

High-‐impact aerobics = 1

Low-‐impact aerobics = 4

Jazzercise = 1

Step exercise = 2

7 0

3 years ago

Can you help my brother with this question 3 pls

cricket20 [7]

They are not equivalent fractions. You will have to turn 3/4 into an 8th, so multiply it by two, (6/8) and plot that on a graph.

7 0

3 years ago

Let f be continuous on [0, a] and differentiable on (0, a), Prove that if f(a)=0 then there is at least one value of x in (0, a)

asambeis [7]

Answer:

See picture attached

Step-by-step explanation:

6 0

3 years ago