Let A be some subset of a universal set U. The "complement of A" is the set of elements in U that do not belong to A.
For example, if U is the set of all integers {..., -2, -1, 0, 1, 2, ...} and A is the set of all positive integers {1, 2, 3, ...}, then the complement of A is the set {..., -2, -1, 0}.
Notice that the union of A and its complement make up the universal set U.
In this case,
U = {1, 2, 3, 6, 10, 13, 14, 16, 17}
The set {3, 10, 16} is a subset of U, since all three of its elements belong to U.
Then the complement of this set is all the elements of U that aren't in this set:
{1, 2, 6, 13, 14, 17}
Answer:
B. x=6
move all terms to the left that don't contain x to the right side and solve.
Answer:
6x-15 = 4x+12
Step-by-step explanation:
3*2x = 6x
3*-5 = -15
4*x=4x
4*3=12
6x-15 = 4x+12
Answer:
the equation of the axis of symmetry is 
Step-by-step explanation:
Recall that the equation of the axis of symmetry for a parabola with vertical branches like this one, is an equation of a vertical line that passes through the very vertex of the parabola and divides it into its two symmetric branches. Such vertical line would have therefore an expression of the form: 
, being that constant the very x-coordinate of the vertex.
So we use for that the fact that the x position of the vertex of a parabola of the general form: 
, is given by:
which in our case becomes:
Then, the equation of the axis of symmetry for this parabola is:
Answer:
1st . The shaded region of the graph ....
2nd. The graph line is solid.
4th. The ordered pair (2 ; 5) is part of the solution set.
Step-by-step explanation:
. Because y is <u>greater</u> or equal than the line, everything above the line is part of the solution.
. Since y is greater or<u> equal</u>, the line is solid. If y was only greater the line would have been dotted.
. The pair (2 ; 5) represent the x = 2 w/ y = 5, and reading the graph you can see the at this point the lines passes through it.
