Decide weather a triangle could have the given angles measures explain your responds 140,70,186

Putting soil is sold in bags that contain 1/2 cubic foot of soil. Estimate how many bags Rylee should buy.

kap26 [50]

Answer:

Ok. So, I can't see the image. Buttttt, depending on how many cubic feet she wants. If she wanted 5.5 cubic feet of soil, she would buy 10 bags of soil. Each showing 1/2 of a cubic foot. Use your fingers to help saying, " Half, One, One and a half, two, two and a half...." So on and so forth.

Step-by-step explanation:

8 0

3 years ago

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What is the value of 4/15 divided by 2/3

ruslelena [56]

Answer:

0.5

Step-by-step explanation:

I'm guessing os yeahhh

6 0

3 years ago

Neil is a drummer who purchases his drumsticks online. When practicing with the newest pair, he notices they feel heavier than u

Fynjy0 [20]

Answer:

The probability of the stick's weight being 2.33 oz or greater is 0.0041 or 0.41%.

Step-by-step explanation:

Given:

Weight of a given sample (x) = 2.33 oz

Mean weight (μ) = 1.75 oz

Standard deviation (σ) = 0.22 oz

The distribution is normal distribution.

So, first, we will find the z-score of the distribution using the formula:

$z=\frac{x-\mu}{\sigma}$

Plug in the values and solve for 'z'. This gives,

$z=\frac{2.33-1.75}{0.22}=2.64$

So, the z-score of the distribution is 2.64.

Now, we need the probability $P(x\geq 2.33 )=P(z\geq 2.64)$ .

From the normal distribution table for z-score equal to 2.64, the value of the probability is 0.9959. This is the area to the left of the curve or less than z-score value.

But, we need area more than the z-score value. So, the area is:

$P(z\geq 2.64)=1-0.9959=0.0041=0.41\%$

Therefore, the probability of the stick's weight being 2.33 oz or greater is 0.0041 or 0.41%.

5 0

3 years ago

Find the probability if two dice are rolled. (Enter the value of probability in decimals. Round the answer to three decimal plac

enyata [817]

The probability of getting a total of 8 when two dice are rolled is 0.139 when the answer is rounded to three decimal places.

<h3>What is meant by Probability?</h3>

Numerous uses of mathematics' probability formula may be found. Probability can be used, for instance, to determine the likelihood that a certain marketing would really be successful in generating fresh customers. Calculating the likelihood of something happening is another use of probability.

Let's examine what probability is, how to compute the probabilities of single and many random occurrences, and how the terms probability and odds vary from one another.

The likelihood that an event like rolling two dice will occur is determined by probability:

P(A) = f / N

Odds and probability are connected, but the probability determines the odds. Probability is required before calculating the likelihood of an occurrence.

The probability is P(getting a total of 8 from both dices)=5/36= 0.139.

To learn more about Probability, visit:

brainly.com/question/23554593

#SPJ4

4 0

1 year ago

3. The Food Marketing Institute shows that 17% of households spend more than $100 per week on groceries. Assume the population p

damaskus [11]

Answer:

A)sample proportion = 0.17, the sampling distribution of p can be calculated/approximated with normal distribution of sample proportion = 0.17 and standard error/deviation = 0.013281

B) 0.869

C)0.9668

Step-by-step explanation:

A) p ( proportion of population that spends more than $100 per week) = 0.17

sample size (n)= 800

the sample proportion of p = 0.17

standard error of p = $\sqrt{\frac{p(1-p)}{n} }$ = 0.013281

the sampling distribution of p can be calculated/approximated with

normal distribution of sample proportion = 0.17 and standard error/deviation = 0.013281

B) probability that the sample proportion will be +-0.02 of the population proportion

= p (0.17 - 0.02 ≤ P ≤ 0.17 + 0.02 ) = p( 0.15 ≤ P ≤ 0.19)

z value corresponding to P

Z = $\frac{P - p}{standard deviation}$

at P = 0.15

Z = (0.15 - 0.17) / 0.013281 = = -1.51

at P = 0.19

z = ( 0.19 - 0.17) / 0.013281 = 1.51

therefore the required probability will be

p( -1.5 ≤ z ≤ 1.5 ) = p(z ≤ 1.51 ) - p(z ≤ -1.51 )

= 0.9345 - 0.0655 = 0.869

C) for a sample (n ) = 1600

standard deviation/ error = 0.009391 (applying the equation for calculating standard error as seen in part A above)

therefore the required probability after applying

z = $\frac{P-p}{standard deviation}$ at p = 0.15 and p = 0.19

p ( -2.13 ≤ z ≤ 2.13 ) = p( z ≤ 2.13 ) - p( z ≤ -2.13 )

= 0.9834 - 0.0166 = 0.9668

7 0

3 years ago

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