If Keith is represented by x, and Joe is three less than Keith, Troy is represented by x-3.
Then, we know that Joe exercises for twice the amount of time as Troy, we multiply the expression for Joe by two.
Keith = x
Troy = x-3
Joe = 2(x-3)
the two consecutive even integers are:
x
x+2
x+x+2=2
2x+2=2
2x=0
x=0
x+2=2
Answer:
5x + y = -48
Step-by-step explanation:
(y + 3)/(x + 9) =m
=> y + 3 = -5x -45
=> 5x + y + 48 = 0
2×3=6. And 1/2(2×2)=2. 2+6=8. 8 square units.
Answer:
h(-3) = -5
Step-by-step explanation:
h(-3) = -I 2-(-3) I
Two negatives makes a positive: -(-3) = +3 or 3
h(-3) = -I 2+3 I
h(-3) = -I 5 I
*There is a negative that lies outside of the absolute value lines, which makes everything positive.
Making sure the 5 is positive, remove the absolute value lines.
h(-3) = - +5
The negative sign is still there.
A negative and a positive makes a negative.
h(-3) = -5
