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Dovator [93]
2 years ago
5

Evaluate: ab – bc if a = 4, b = 3, and c = 2 ab - bc =

Mathematics
2 answers:
lorasvet [3.4K]2 years ago
8 0
(4)(3)-(3)(2) = 12-6 = 6
defon2 years ago
4 0

Answer:

6

Step-by-step explanation:

To evaluate the expression if a = 4, b = 3, and c = 2, substitute those values for the variables and solve. So, substitute 4 for a, 3 for b, and 2 for c, then simplify by the correct order of operations, PEMDAS:

ab - bc \\(4)(3)-(3)(2)\\= 12 - 6 \\= 6

Therefore, the answer is 6.

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F⃗ (x,y)=−yi⃗ +xj⃗ f→(x,y)=−yi→+xj→ and cc is the line segment from point p=(5,0)p=(5,0) to q=(0,2)q=(0,2). (a) find a vector pa
DerKrebs [107]

a. Parameterize C by

\vec r(t)=(1-t)(5\,\vec\imath)+t(2\,\vec\jmath)=(5-5t)\,\vec\imath+2t\,\vec\jmath

with 0\le t\le1.

b/c. The line integral of \vec F(x,y)=-y\,\vec\imath+x\,\vec\jmath over C is

\displaystyle\int_C\vec F(x,y)\cdot\mathrm d\vec r=\int_0^1\vec F(x(t),y(t))\cdot\frac{\mathrm d\vec r(t)}{\mathrm dt}\,\mathrm dt

=\displaystyle\int_0^1(-2t\,\vec\imath+(5-5t)\,\vec\jmath)\cdot(-5\,\vec\imath+2\,\vec\jmath)\,\mathrm dt

=\displaystyle\int_0^1(10t+(10-10t))\,\mathrm dt

=\displaystyle10\int_0^1\mathrm dt=\boxed{10}

d. Notice that we can write the line integral as

\displaystyle\int_C\vecF\cdot\mathrm d\vec r=\int_C(-y\,\mathrm dx+x\,\mathrm dy)

By Green's theorem, the line integral is equivalent to

\displaystyle\iint_D\left(\frac{\partial x}{\partial x}-\frac{\partial(-y)}{\partial y}\right)\,\mathrm dx\,\mathrm dy=2\iint_D\mathrm dx\,\mathrm dy

where D is the triangle bounded by C, and this integral is simply twice the area of D. D is a right triangle with legs 2 and 5, so its area is 5 and the integral's value is 10.

4 0
2 years ago
What is the solution of log(3x − 2)125 = 3?
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3 years ago
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5x-9 = 3x+3

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plz mark branliest, hopoe this helps :)

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7 0
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