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2 years ago

3 or 4 more we got this

Mathematics

2 answers:

dlinn [17]2 years ago

5 0

Answer:

15/40

Step-by-step explanation:

the numerator decreases by 3

umka2103 [35]2 years ago

3 0

The answer is 15/40 because each time it decreases by 3.

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A trough has ends shaped like isosceles triangles, with width 5 m and height 7 m, and the trough is 12 m long. Water is being pu

Svet_ta [14]

Answer:

$\dfrac{dh}{dt}=21 \text{m/min}$

the rate of change of height when the water is 1 meter deep is 21 m/min

Step-by-step explanation:

First we need to find the volume of the trough given its dimensions and shape: (it has a prism shape so we can directly use that formula OR we can multiply the area of its triangular face with the length of the trough)

$V = \dfrac{1}{2}(bh)\times L$

here L is a constant since that won't change as the water is being filled in the trough, however 'b' and 'h' will be changing. The equation has two independent variables and we need to convert this equation so it is only dependent on 'h' (the height of the water).

As its an isosceles triangle we can find a relationship between b and h. the ratio between the b and h will be always be the same:

$\dfrac{b}{h} = \dfrac{5}{7}$

$b=\dfrac{5}{7}h$ this can be substituted back in the volume equation

$V = \dfrac{5}{14}h^2L$

the rate of the water flowing in is:

$\dfrac{dV}{dt} = 6$

The question is asking for the rate of change of height (m/min) hence that can be denoted as: $\frac{dh}{dt}$

Using the chainrule:

$\dfrac{dh}{dt}=\dfrac{dh}{dV}\times \dfrac{dV}{dt}$

the only thing missing in this equation is dh/dV which can be easily obtained by differentiating the volume equation with respect to h

$V = \dfrac{5}{14}h^2L$

$\dfrac{dV}{dh} = \dfrac{5}{7}hL$

reciprocating

$\dfrac{dh}{dV} = \dfrac{7}{5hL}$

plugging everything in the chain rule equation:

$\dfrac{dh}{dt}=\dfrac{dh}{dV}\times \dfrac{dV}{dt}$

$\dfrac{dh}{dt}=\dfrac{7}{5hL}\times 6$

$\dfrac{dh}{dt}=\dfrac{42}{5hL}$

L = 12, and h = 1 (when the water is 1m deep)

$\dfrac{dh}{dt}=\dfrac{42}{5(1)(12)}$

$\dfrac{dh}{dt}=21 \text{m/min}$

the rate of change of height when the water is 1 meter deep is 21 m/min

6 0

3 years ago

Read 2 more answers

If a pool holds 22,000 gallons, how long will it take to fill the pool at a rate of 400 gallons per minute, rounded off to the n

nalin [4]

400x=22,000

22,000/400=x

55=x Hopefully this is right, and hopefully this helps

8 0

2 years ago

Read 2 more answers

A length is measured at 21 cm correct to two significant figures, what is the lower bound of the length and upper bound?

Andreyy89

Answer:

20.5 and 21.5

Step-by-step explanation:

It says 2 significant figures so the least it can possibly be is 0.5 less and the most it can be is 0.5 more as if it was, lets say 20.4 it would round down to 20 not 21.

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2 years ago

14. Determine whether x3 is O(g(x)) for each of these functions g(x). a) g(x) = x2 b) g(x) = x3 c) g(x) = x2 + x3 d) g(x) = x2 +

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Answer:

Answer and explanation with steps are in the following attachments

Step-by-step explanation:

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2 years ago

A bouquet of lilies and tulips has 20 flowers.

motikmotik

Answer:8 lilies and 12 tulips; total of 20 flowers.

Step-by-step explanation:

8 lilies for $3 each equals $24. 12 tulips for $2 each equals $24. Add that together and the total for the bouquet is $48.

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3 years ago