1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
goldenfox [79]
3 years ago
6

The amount of oil used by a ship traveling at a uniform speed varies jointly with the distance and the square of the speed. The

ship uses 34 barrels of oil in traveling 60 miles at 20 mi/h. How many barrels of oil are used when the ship travels 32 miles at 23 mi/h? Round your answer to the nearest tenth of a barrel, if necessary.
Mathematics
1 answer:
frosja888 [35]3 years ago
7 0

Answer:

Step-by-step explanation:

Joint variation has the equation

y = kxz

k is the constant of variation and needs to be solved for using the initial conditions, then filled in later to another equation related to the given info to solve for something else.  We are given y = amount of oil used, x = distance traveled, z-squared is the speed.  Our equation looks like this, to be exact:

y=kxz^2

Filling in with the initial conditions:

34=k(60)(20)^2 which gives us the

k = .0014166667

Now we need to find the amount of oil used, y, under other circumstances, but this time we have our k.

y=(.0014166667)(32)(23)^2

which gives us that the amount of oil used, when rounded to the tenths,

y = 24.0 barrels

You might be interested in
Can someone help me please ASAP
Mamont248 [21]
Answer

25f + 100c <span>≤ 700

hope it  helps</span>
6 0
3 years ago
Subtract 8 feet from 9 yards, 1 foot
Advocard [28]

Answer:

20 feet

Step-by-step explanation:

There are 3 feet in a yard, so 9 yards and 1 foot = 28 feet. You find this by multiplying 9x3 = 27 and adding the extra foot, which makes it 28. To find the final answer just subtract 8 from 28, which gives you 20.

4 0
3 years ago
The equation d=4 -1/15t represents your distance from home,d, for each minute you walk,t. If you graphed this equation, determin
Jobisdone [24]
When you graph an equation, it should be dependent variable against the independent variable. For this problem, the independent variable is the time, so this is along the x-axis. The dependent variable is d, so this is along the y-axis. Since the slope is Δy/Δx, then it is also equivalent to Δd/Δt. Therefore, the answer is B.
6 0
3 years ago
Read 2 more answers
IT COST $9 TO GO TO PETE'S POTTERY PLACE TO MAKE YOUR OWN BOWLS $3 PER BOWL. NATALIE GOES TO PETE'S POTTERY PLACE AND MAKES B BO
S_A_V [24]
C= 5(9*3b)
C= 5(9*12)
C= 5(108)
C=540
8 0
3 years ago
A factory produces bottled water at a rate of 2,000 cases per hour. They know that 1.14% of the cases must be rejected because a
IRINA_888 [86]
1.14 per 100 or 1.14:100 or \frac{1.14}{100}

\frac{1.14}{100} =  \frac{n}{2000}

I will multiply the numerator by 20 because multiplying by 20 is how 100 became 2000
22.8 cases are rejected per hour.
4 0
3 years ago
Other questions:
  • A machine produces
    14·1 answer
  • A circular piece of metal has a radius of 3.5 meters. The metal sells for $3.25 per m². What is the total cost of the circular p
    9·2 answers
  • Which answer is the solution set in simpliest form 4x-1/3=7/1
    5·1 answer
  • Please helpp faster WiLL MARKED BRAINLIEST !!
    14·1 answer
  • 3/4 x 5/6 simplified
    8·1 answer
  • Select the correct answer. Each statement describes a transformation of the graph of
    6·1 answer
  • Zan has created this rule for generating sequences of whole numbers. If a number is 25 or less, double the number. If a number i
    14·1 answer
  • How much paper will be needed to cover the triangular prism shown?
    12·2 answers
  • Subtract: 3.8 - 2.923. Explain in your own words how you would solve this, in detail, from start to finish.
    7·1 answer
  • Adult tickets for the evening show at XD Theater are $16 and children's tickets are $8. If the theater seats 282 people, how man
    5·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!