Answer:
6 Total lemons
Step-by-step explanation:
1 1/2 lemons per 1 liter of lemonade
1 1/2 times 4
= 6 total lemons
Answer:
Step-by-step explanation:
Given that :
The enormous sinkhole that appeared in the middle of Guatemalan neighborhood in the year 2010 swallowed a three story building above it and the sinkhole has an estimated depth of about 100 feet
How much material is needed to fill the sinkhole?
Then , the material needed to fill the sinkhole will be dependent on the volume of the sinkhole.
Determine what information is needed to answer the question.
The information that is needed to answer this question are:
the base area of the sinkhole will be required; &
the height should also be known
if the base area is determined then we can proceed to determine how much material is needed to be calculated.
Do you think your estimate is more likely to be too high or too low
No, the estimate is not likely to be too high or too low rather the estimate of the material required will be almost equal to the volume of the sinkhole, but that does not implies that it will be exactly the same since the sinkhole is not uniform and regular in shape.
<h3>Given :-</h3>
<h3>To Find :-</h3>
<h3>Solution :-</h3>
☼︎ <u>Radius of the Circle</u>;
<h3>Using Formula:</h3>

<u>Putting values in the formula;</u>









henceforth, the Radius of a circle is 14 cm ...!!
The answer is: "
40 cm " .
_________________________________________________________<u>Note</u>:_________________________________________________________
;
Solve for "x" (in "cm" ) ;
→ 5x = 200 * 1 ;
→ 5x = 200 ;
Divide each side of the equation by "5" ;
to isolate "x" on one side of the equation; & to solve for "x" ;
→ 5x / 5 = 200 / 5 ;
to get:
→ x = 40 .
___________________________________________________________The answer is: "
40 cm " .
___________________________________________________________
Answer:
Just try to make it make sense to you.
Step-by-step explanation:
For instance, a + 1 = 5
a = 4
We know that we should switch the terms as when it comes to normal numbers ,10 + 1 = 11 , 10 = 11-1. Therefore, the only trick is not to memorise, but try to understand the logic behind it. Hope this helps in some way???