Question

A semicircle has the radius of 2 4/5. What is its area? leave your answers in term of π

Answer 1

Answer:

$11\dfrac{13}{25}\pi$

Step-by-step explanation:

r = Radius of semicircle = $2\dfrac{4}{5}=\dfrac{24}{5}\ \text{units}$

Area of semicircle is given by

$A=\dfrac{\pi r^2}{2}\\\Rightarrow A=\dfrac{\pi \left(\dfrac{24}{5}\right)^2}{2}\\\Rightarrow A=\dfrac{288}{25}\pi=11\dfrac{13}{25}\pi\ \text{sq. units}$

The area of the semicircle is $11\dfrac{13}{25}\pi\ \text{sq. units}$.