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valentinak56 [21]
3 years ago
12

A semicircle has the radius of 2 4/5. What is its area? leave your answers in term of π

Mathematics
1 answer:
Ratling [72]3 years ago
4 0

Answer:

11\dfrac{13}{25}\pi

Step-by-step explanation:

r = Radius of semicircle = 2\dfrac{4}{5}=\dfrac{24}{5}\ \text{units}

Area of semicircle is given by

A=\dfrac{\pi r^2}{2}\\\Rightarrow A=\dfrac{\pi \left(\dfrac{24}{5}\right)^2}{2}\\\Rightarrow A=\dfrac{288}{25}\pi=11\dfrac{13}{25}\pi\ \text{sq. units}

The area of the semicircle is 11\dfrac{13}{25}\pi\ \text{sq. units}.

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Explanation:

The domain is the set of all possible input x values. The range is the set of all possible y outputs.

Plug in each x value from the domain, one at a time, to get its corresponding range y value.

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Start with x = -3

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So -3 is in the range.

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Move onto x = -1

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All of those values form the set {-3, 1, 5} which is the complete range.

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