The two non negative real numbers with a sum of 64 that have the largest possible product are; 32 and 32.
<h3>How do we solve the nonnegative real numbers?</h3>
Let the two numbers be x and y.
Thus, if their sum is 64, then we have;
x + y = 64
y = 64 - x
Their product will be;
P = xy
Putting (64 - x) for y in the product equation we have;
P = (64 - x)x
P = 64x - x²
Since the product is maximum, let us find the derivative;
P'(x) = 64 - 2x
At P'(x) = 0, we have;
64 - 2x = 0
2x = 64
x = 64/2
x = 32
Thus; y = 64 - 32
y = 32
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Answer:
See below.
Step-by-step explanation:
6x-2≤9
+2 +2
6x≤11
/6 /6
x≤11/6
4+3x>15
-4 -4
3x>11
/3 /3
x>11/3
-hope it helps
Answer:
122.5 m
Step-by-step explanation:
s = ½g.t²
= ½×9.8×5² = 122.5
Answer:12300
Step-by-step explanation:12.3x1000
Answer:
3/5=x/z
Step-by-step explanation:
7x=3y
7(3)=3(7)
21=21
5y=7z
5(7)=7z (plug in the seven from the first step)
35=7z
then divide both sides by 7
5=z
therefore, X/Z=3/5