Can you please help me with this?
1 answer:
You might be interested in
The complete question in the attached figure
step 1
find the area of the wall
[area of the wall]=[area of rectangle]+[area of triangle]
[area of the wall]=[3*2]+[3*1/2]----> 7.5 m²
1 m²-------> 10.7639 ft²
area of the wall------> 7.5*10.7639------> 80.73 ft²
we know that
1 can of paint covers an area of --------> 24 ft²
x---------------------------------------------> 80.73 ft²
x=80.73/24---------> x=3.36 can of paints
the answer is
T<span>he fewest number of cans is 4</span>
step 1
find the area of the wall
[area of the wall]=[area of rectangle]+[area of triangle]
[area of the wall]=[3*2]+[3*1/2]----> 7.5 m²
1 m²-------> 10.7639 ft²
area of the wall------> 7.5*10.7639------> 80.73 ft²
we know that
1 can of paint covers an area of --------> 24 ft²
x---------------------------------------------> 80.73 ft²
x=80.73/24---------> x=3.36 can of paints
the answer is
T<span>he fewest number of cans is 4</span>
The value of the x is 2 and the value of the y is 0 in the system of equation 3y=x-2, y=-2x+4.
<h3>What is a linear equation?</h3>It is defined as the relation between two variables, if we plot the graph of the linear equation we will get a straight line.
If in the linear equation, one variable is present, then the equation is known as the linear equation in one variable.
We have a system of the equation:
3y=x-2 ..(1)
y=-2x+4 ...(2)
From the equation (2) take the value of y and plug in the equation (1)
3(-2x+4) = x -2
-6x + 12 = x - 2
7x = 14
x = 14/7
x = 2
Plug this value in the equation (2)
y = -2(2) + 4
y = 0
Thus, the value of the x is 2 and the value of the y is 0 in the system of equation 3y=x-2, y=-2x+4.
Learn more about the linear equation here:
#SPJ1
