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Ivenika [448]
3 years ago
5

A. 6 B. ⟌50 C. ⟌34 D. 4 Which one?

Mathematics
1 answer:
AfilCa [17]3 years ago
6 0

Answer:

C

Step-by-step explanation:

3^2 + 5^2 = x^2

9 + 25 = x^2

x^2 = 34

x = sqrt(34)

so the answer is C

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Margo used 864 heads to make a necklace for the art club. She made 24 necklaces with the beads. If each necklace has the same nu
Taya2010 [7]

Answer:

36

Step-by-step explanation:

if you start with 864 and she made 24 necklaces, your math equation would be 864 divided by 24 = 36

4 0
3 years ago
Read 2 more answers
Reese is selling lemonade at the parade. He gets to keep 10% of the money he collects. A large lemonade is $7.00 and a small lem
jeka94

Answer:

We conclude that the simplified expression is:

0.10\left(7l\:+\:2s\right)=0.7l+0.2s

Step-by-step explanation:

Given the expression

0.10\left(7l\:+\:2s\right)

Apply the distributive law:   a(b+c) = ab+ac

a = 0.1, b = 7l, c = 2s

0.10\left(7l\:+\:2s\right)=0.1\cdot \:7l+0.1\cdot \:2s

                       =7\cdot \:0.1l+2\cdot \:0.1s

                        =0.7l+0.2s

Therefore, we conclude that the simplified expression is:

0.10\left(7l\:+\:2s\right)=0.7l+0.2s

4 0
3 years ago
Is M a midpoint of line AB= ? AB= 27 and MB =14 <br> A maybe <br> B can’t be <br> C no <br> D yes
My name is Ann [436]
The answer is B/C.—M is in fact NOT a midpoint of line AB. This is because to be a midpoint the distance between both endpoints and the midpoint must me equal. If AB has equaled 28 then is would be, but in this case NO. To get AM you just need to do 27-14. AM would be 13 (if you need that too)
6 0
3 years ago
Determine whether the given lengths can be sides of a right triangle. Which of the following are true statements. A.The lengths
Stels [109]

Answer:

Given sides 12, 16 and 20 can be the sides of right triangle.

Step-by-step explanation:

Sides of right triangle always follow the Pythagoras theorem.

i.e (base)^2 + (Height)^2 = (Hypotenuse)^2

For the given Lengths 7, 40 and 41

We need to check if

7^2 + 40^2 =41^2 \\or\\ 7^2 + 40^2 \neq41^2

Since \\7^2 + 40^2 = 1649\\and \\41^2 = 1681

That means, \\ 7^2 + 40^2 \neq 41^2

hence 7,40 and 41 can not be the sides of right triangle.

Next,

Given sides 12,16 and 20.

Again follow the similar process used in the above problem.

12^2 + 16^2 =400\\And \\20^2 = 400\\Since 12^2 + 16^2 = 20^2

Therefore given sides 12,16 and 20 can be the sides of right triangle.


7 0
3 years ago
How do i solve x+1,5=<br>please help!!
iren [92.7K]
You're in elementary??
7 0
3 years ago
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