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masha68 [24]
3 years ago
8

I tried multiplying it but I still can’t figure it out please please help

Mathematics
1 answer:
neonofarm [45]3 years ago
3 0
The answer is 88 5/6 .   If you were stuck try turning the fractions into improper fractions and multiply both of them and later divide the numerator by the denominator to have a mixed number.  You can later simplify the fraction to get 88 5/6.  If you need help don't be afraid to tell me in the comments!   Hope this helps :)
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3 years ago
Simplify using the vertical method. (3k + 4)(3k^2 – 5k – 3)
liubo4ka [24]

Answer:

9k^{3} -3k^{2}-29k-12

Step-by-step explanation:

Step 1: Expand by distributing sum groups.

3k(3k^{2} -5k-3)+4(3k^{2} -5k-3)

Step 2: Expand by distributing terms.

9k^{3} -15k^{2} -9k+4(3k^{2} -5k-3)

Step 3: Expand by distributing terms.

9k^{3}-15k^{2} -9k+12k^{2} -20k-12

Step 4: Collect like terms.

9k^{3}+(-15k^{2}  +12k^{2} )+(-9k-20k)-12

Step 5: Simplify.

9k^{3} -3k^{2}-29k-12

3 0
3 years ago
Which sets are not closed under subtraction
anastassius [24]

If you're referring to the different sets of real numbers, it's the ones that you could try to do subtraction and not get an answer that still in that set.

For example, natural numbers (aka 1, 2, 3, 4, ...) are not, because 7 - 11 = -4 and -4 is not a natural number.

Also, whole numbers (aka 0, 1, 2, 3, 4, ...) has the same issue.

Basically any set of real numbers that doesn't include negative numbers will have this issue.

6 0
3 years ago
How many minutes of calling time do the plans cost the same amount ?
Mama L [17]
D 200 minutes

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Answer is D
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