Answer:
9+1/4g = h
Step-by-step explanation:
We have to assume that the speed before being stuck was sufficient to get to the destination on time had there been no delay. Call that speed "s" in km/h.
Since 200 km is "halfway", the total distance must be 400 km.
time = distance / speed
total time = (time for first half) + (delay) + (time for second half)
400/s = 200/s + 1 + 200/(s+10) . . . .times are in hours, distances in km
200/s = 1 + 200/(s+10) . . . . . . . . . . subtract 200/s
200(s+10) = s(s+10) +200s . . . . . . .multiply by s(s+10)
0 = s² +10s - 2000 . . . . . . . . . . . . . .subtract the left side
(s+50)(s-40) = 0
Solutions are s = -50, s = 40
The speed of the bus before the traffic holdup was 40 km/h.
(5 x 12) ÷ 2 = 30 (area of triangle)
40 x 12 = 480 (area of rectangle)
12 ÷ 2 = 6 (radius of semicircle)
3.14 x 6^2 = 3.14 x 36 = 113.04
113.04 ÷ 2 = 56.52 (area of semicircle)
30 + 480 + 56.52 = 566.52 square feet
