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3 years ago

(2-7m^6)^2 i dont know this

1 answer:

7 0

(2-7m^6)^2

rearrange terms:

(2-7m^6)^2

(-7m^6 + 2)^2

expand the squares:

(-7m^6 + 2)^2

(-7m^6 + 2)(-7m^6 + 2)

distribute:

(-7m^6 + 2)(-7m^6 + 2)

-7(-7m^6 + 2) • m^6 + 2(-7m^6 + 2)

distribute:

-7(-7m^6 + 2) • m^6 + 2(-7m^6 + 2)

49m^12 - 14m^6 + 2(-7^6 +2)

distribute:

49m^12 - 14m^6 + 2(-7^6 +2)

49m^12 - 14m^6 - 14m^6 + 4

combine like terms:

49m^12 - 14m^6 - 14m^6 + 4

49m^12 - 28m^6 + 4

solution:

49m^12 - 28m^6 + 4

please mark brainliest and hope it helps

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According to Thomson Financial, last year the majority of companies reporting profits had beaten estimates. A sample of 162 comp

vova2212 [387]

Answer:

0.1790

0.0738 , 0.5800, 0.7040

354

Step-by-step explanation:

a. Given:

n = 162

x = 29

c = 95%

The point estimate of the population proportion is the sample proportion. The sample proportion is the number of successes divided by the sample size:

p = x/n

= 29/162

= 0.1790

b. Given:

n=162

x = 110

c = 95%

The point estimate of the population proportion is the sample proportion. The sample proportion is the number of successes divided by the sample size:

p = x/n

=110/162

=0.6790

For confidence level 1 – $\alpha$ = 0.95, determine z_ $\alpha$ /2 = z_0.025 using table 1 (look up 0.025 in the table, the z-score is then the found z-score with opposite sign):

z_ $\alpha$ /2 = 1.96

The margin of error is then:

E = z_ $\alpha$ /2*√p(1-p)/n =1.96* √0.6790(1-0.6790)/162 =0.0738

The boundaries of the confidence interval are then:

p-z_ $\alpha$ /2*√p(1-p)/n = 0.6790-1.645√ 0.6790(1- 0.6790)/162 = 0.5800

p+z_ $\alpha$ /2*√p(1-p)/n = 0.6790+1.645√ 0.6790(1- 0.6790)/162 = 0.7040

c. Given:

n = 162

x = 110

c = 95%

The point estimate of the population proportion is the sample proportion. The sample proportion is the number of successes divided by the sample size:

p =x/n

=0.6790

Formula sample size:

p known: n = [z_ $\alpha$ /2 ]^2*pq/E^2

= [z_ $\alpha$ /2 ]^2*p(1-p)/E^2

n = [z_ $\alpha$ /2 ]^2*0.25/E^2

For confidence level 1 – $\alpha$ = 0.95, determine z_ $\alpha$ /2 = z_o.025 using table 1 (look up 0.025 in the table, the z-score is then the found z-score with opposite sign):

z_ $\alpha$ /2 = 1.96

p is known, then the sample size is (round up!):

n =[z_ $\alpha$ /2 ]^2*p(1-p)/E^2

= 354

8 0

3 years ago

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Answer:

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Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

What's the answer for x/2-5=3

kifflom [539]

X=16

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4 0

3 years ago

Joe has 4/5 as much money as bob. Tim has $50 more than joe. Rita has $150, which is $35 more than bob. How much money does tim

lesantik [10]

Rita = $150

Bob = $150 - $35 = $115 Bob has $115

Joe = $115 divided by 5 = $23 $23 x 4 = $92 Joe Has $92

Tim = Has $50 more then joe, $92 + $50 = $142 Tim has $142

3 0

3 years ago

Sterre charges $ 3 5 $35dollar sign, 35 to file tax returns, but files for free if she only needs the easiest form. Then she don

blagie [28]

Given:

$35 is charged per form, but $0 if only the easiest form is filed.
$2 donated for every single tax return filed (since it is not explicitly mentioned otherwise, I will assume she donates $2 whether she charges $35 or does it for free)
Total amount charged for the full year = $7245
Total amount donated for the full year = $1242

To Find: The number of forms for which Sterre charged $35 and the number of forms Sterre did it for free.

Concept:

We can make use of the Unitary Method here. Given the number of units in a group, the Unitary Method can be used to find the value of a single unit or and individual unit when we are given the value for a group.

So,

Value of Single Unit = Value of Entire Group of Units ÷ Number of Units in the Group

Explanation & Calculation:

We are given that Sterre charged $7245 for the full year. Taking each Unit as the $35 type of form, and value of each Unit would be the amount that Sterre charges per form which is obviously $35, we can find the number of $35 forms using the expression written above.

So, putting in the values into the expression,

$35 = $7245 ÷ number of $35 forms

Therefore, number of $35 forms = $7245 ÷ $35

Using simple division, number of $35 forms = 207

Next, we are given Sterre donated $1242 in the full year and she donates $2 for every form (whether it is the $35 form or the free form).

If this time, we define each Unit as being each form (both $35 form and free form), value of each unit we define as the $2 donation money, we see that the value of the full group of units is $1242.

So, putting the values into the expression,

$2 = $1242 ÷ total number of forms

Therefore, total number of forms = $1242 ÷ $2

Using simple division, total number of forms = 621

Conclusion:

Sterre has filed a total of 621 tax returns (both charged and for free).

Of these 621 returns filed, for 207 forms, Sterre charged $35.

The number of returns Sterre filed for free (that is, the easiest forms) is

Total number of forms - Chargeable forms = 621 - 207 = 414

Thus, Sterre filed 414 tax returns for free.

8 0

3 years ago