This question has extraneous info to trick you.
f(x) = g(x)h(x) ⇒ f'(x) = g'(x)h'(x) . Letting x = 10, we get f'(10) = g'(10)h'(10). then just plug in the values provided. g(10) and h(10) are there to throw you off, just use g'(10) and h'(10).
So f'(10), pronounced "eff prime of ten", = 0 * 35 = 0.
If the question were asking for f(10) instead of f'(10) then you would use g(10) and h(10), ⇒-4*560=90.
We are given a concave spherical mirror with the following dimensions:
Radius = 60 cm; D o = 30 cm
Height = 6 cm; h o = 6 cm
First, we need to know the focal length, f, of the object (this should be given). Then we can use the following formulas for calculation:
Assume f = 10 cm
1/ f = 1 /d o + 1 / d i
1 / 10 = 1 / 30 + 1 / d i
d i = 15 cm
Then, calculate for h i:
h i / h o = - d i / d o
h i / 6 = - 15 / 30
h i = - 3 cm
Therefore, the distance of the object from the mirror is 3 centimeters. The negative sign means it is "inverted".
Answer:
The answer is (x + 3) (x - 7) = 0
Step-by-step explanation:
x² - 4x = 21
x² - 4x - 21 = 0
x² - 7x + 3x - 21 = 0
x(x - 7) + 3(x - 7) = 0
(x + 3) (x - 7) = 0
Thus, The answer is (x + 3) (x - 7) = 0
<em><u>-TheUnknownScientist</u></em>
<span>I have graphed the given coordinates of both pentagons. The reflection was across the y-axis where coordinates of Pentagon PQRST (-x,y) resulted to Pentagon P'Q'R'S'T' (x,y). The line of reflection between the pentagons was x = 0. Line of reflection is the midway between the pre-image and its reflection.</span>
