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2 years ago

Which two operations will solve this equation: 4x − 5 = 1

Mathematics

1 answer:

Alex_Xolod [135]2 years ago

8 0

Answer:

4x -5=1

4x= 1+5

x=6/4

x= 1.5

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Two angles are vertical angles. One measures 39.2 degrees. What is

Zarrin [17]

Answer:

39.2°

Step-by-step explanation:

Vertical angles are always congruent.

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2 years ago

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The sum of three consecutive terms of an A.P is 18 and their product is 120. Find the terms?

GarryVolchara [31]

Answer:

2 6 10

Step-by-step explanation:

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2 years ago

Make a table for the following equations<br> y = 2x + 4

nekit [7.7K]

In order to make a table, we sample some x values (whichever we want), and we compute the expression for those value. Each x value will yield a unique y value.

If you need this table to graph the function, you'll only need two points, since this is a line, and having two points you just need to connect them.

Here are some samples, feel free to make more if you need to:

$f(x)=2x+4\implies f(0)=2\cdot 0 + 4 = 4$

$f(x)=2x+4\implies f(1)=2\cdot 1 + 4 = 6$

$f(x)=2x+4\implies f(2)=2\cdot 2 + 4 = 8$

$f(x)=2x+4\implies f(3)=2\cdot 3 + 4 = 10$

$f(x)=2x+4\implies f(4)=2\cdot 4 + 4 = 12$

So, we have the following table

$\begin{array}{c|c}0&4\\1&6\\2&8\\3&10\\4&12\end{array}$

4 0

3 years ago

Using no digits other than 5 and 8, make a 6-digit number, that has the properties below. If it is impossible, write so. Of cour

Anna11 [10]

Since it's a multiple of 24, it has to be a multiple of the factors of 24.

Factors of 24:
2,3,4,6,8,12

You can use some of this knowledge to help create the number.
Since the # needs to be a multiple off 2, the last digit needs to be an 8

All numbers that are multiples of 3 have the property that all of their digits added together have to be a number that is evenly divisible by 3.

so your number will look like:
_ _ _ _ _ 8

so start trying combinations for the other 5 digits that give you a number that is a multiple of 3: 3,6,9,12,15, ect. If you can't find one, then it's impossible

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2 years ago

Among 500 freshmen pursuing a business degree at a university, 315 are enrolled in an economics course, 213 are enrolled in a ma

scoundrel [369]

Answer:

Step-by-step explanation:

Given that among 500 freshmen pursuing a business degree at a university, 315 are enrolled in an economics course, 213 are enrolled in a mathematics course, and 123 are enrolled in both an economics and a mathematics course.

From the above we find that

a) either economics of Math course is

$315+213-123 =405$

Out of 500 students 405 have taken either Math or Economics

Hence

c) student who have taken neither = $500-405 =95$

Exactly one course is either math or economics - both

= $405-123 = 282$

3 0

3 years ago