I'm doing simplifying expressions with exponents

Mathematics

1 answer:

VladimirAG [237]3 years ago

7 0

Answer:

Expressing a number in a power of 2 means that you have to figure out how many times you should multiply 2 by itself so the product will be that number.

The number is expressed as 2^n

For example:

Express 16 as a power of 2:

To get 16, you have to multiply 2 by 4 times.

2 × 2 × 2 × 2 = 16

16 = 2^4

Then the answer is 2^4

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Please Help! (Math)(tanβ)

sertanlavr [38]

Answer:

<u>Find the missing side first.</u>

x = $\sqrt{12^2 - 7^2} = \sqrt{144 - 49} = \sqrt{ 95}$

1) tangent = opposite leg / adjacent leg

tanβ = √95/7
Correct choice is B

2) sine = opposite leg / hypotenuse

sinβ = √95/12
Correct choice is D

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3 years ago

PLEASE HELP ILL GIVE BRAINLIEST

dusya [7]

$(-2+\sqrt{-5})^2\implies (-2+\sqrt{-1\cdot 5})^2\implies (-2+\sqrt{-1}\sqrt{5})^2\implies (-2+i\sqrt{5})^2 \\\\\\ (-2+i\sqrt{5})(-2+i\sqrt{5})\implies +4-2i\sqrt{5}-2i\sqrt{5}+(i\sqrt{5})^2 \\\\\\ 4-4i\sqrt{5}+[i^2(\sqrt{5})^2]\implies 4-4i\sqrt{5}+[-1\cdot 5] \\\\\\ 4-4i\sqrt{5}-5\implies -1-4i\sqrt{5}$

let's recall that the conjugate of any pair a + b is simply the same pair with a different sign, namely a - b and the reverse is also true, let's also recall that i² = -1.

$\cfrac{6-7i}{1-2i}\implies \stackrel{\textit{multiplying both sides by the denominator's conjugate}}{\cfrac{6-7i}{1-2i}\cdot \cfrac{1+2i}{1+2i}\implies \cfrac{(6-7i)(1+2i)}{\underset{\textit{difference of squares}}{(1-2i)(1+2i)}}} \\\\\\ \cfrac{(6-7i)(1+2i)}{1^2-(2i)^2}\implies \cfrac{6-12i-7i-14i^2}{1-(2^2i^2)}\implies \cfrac{6-19i-14(-1)}{1-[4(-1)]} \\\\\\ \cfrac{6-19i+14}{1-(-4)}\implies \cfrac{20-19i}{1+4}\implies \cfrac{20-19i}{5}\implies \cfrac{20}{5}-\cfrac{19i}{5}\implies 4-\cfrac{19i}{5}$