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Temka [501]
3 years ago
6

Find the zeros of the functions f(x)=-x^2+25

Mathematics
2 answers:
goldfiish [28.3K]3 years ago
8 0
The correct answer is 5 as shown in the picture above/below

Damm [24]3 years ago
6 0
The answer is 5!!!!!!!!!!!
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Evaluate another function please
kari74 [83]

Answer:

70, I think

Step-by-step explanation:

f(10)= -10^2- 3(10)

f(10)= 100-30

f(10) = 70

6 0
3 years ago
At any point in time, there could be bicycles, tricycles, and
Aleksandr-060686 [28]

Answer:

There may be 1 or 3 tricycles in the parking lot.

Step-by-step explanation:

Since at any point in time, there could be bicycles, tricycles, and cars in the school parking lot, and today, there are 53 wheels in total, if there are 15 bicycles, tricycles, and cars in total, to determine how many tricycles could be in the parking lot, the following calculation must be performed:

13 x 4 + 1 x 3 + 1 x 2 = 57

11 x 4 + 1 x 3 + 3 x 2 = 53

10 x 4 + 3 x 3 + 2 x 2 = 53

8 x 4 + 5 x 3 + 2 x 2 = 51

10 x 2 + 1 x 3 + 4 x 4 = 39

9 x 3 + 1 x 2 + 5 x 4 = 49

Therefore, there may be 1 or 3 tricycles in the parking lot.

6 0
3 years ago
Evaluate <br><img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B%20%7Bm%7D%5E%7B2%7D%20%20%2B%20%20%7Bm%7D%5E%7B%20-%202%7D%20%2B%20
zysi [14]

Answer:

9.5

Step-by-step explanation:

(0.5^2 + 0.5^-2 + 0.5) / 0.5 = 9.5

Hope this help! :)

4 0
4 years ago
Simplify the expression where possible.<br> (r ^-3 s^2 t) ^4
ASHA 777 [7]

Use\\\\(ab)^n=a^nb^n\\\\ (a^n)^m=a^{n\cdot m}\\-------------------\\\\\left(r^{-3}s^2t\right)^4=\left(r^{-3}\right)^4\left(s^2\right)^4(t)^4=r^{(-3)(4)}s^{(2)(4)}t^4\\\\=\boxed{r^{-12}s^8t^4}\to\boxed{\dfrac{s^8t^4}{r^{12}}}

3 0
3 years ago
PLEASE PLEASE HELP I WILL GIVE THE BRAINLIEST
salantis [7]

Answer:

9.45+189=198.45

Step-by-step explanation:

7 0
3 years ago
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