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stiks02 [169]
3 years ago
10

One British pound was worth 1.5761 Canadian dollar.If a hotel room coat 126 pounds,what must be paid in Canadian dollars.​

Mathematics
2 answers:
Kamila [148]3 years ago
6 0

Answer:

198.5886   or technically 198.58 or 198.59 because you can't have a decimal of a penny.

Step-by-step explanation:

One British pound was worth 1.5761 Canadian dollar, meaning that every pound needed is worth 126 Canadian dollar.

That means you can multiply 1.5761 by 126 to get the Canadian dollar price.

126 x 1.5761 = 198.5886

198.5886 is the Canadian price

Doss [256]3 years ago
5 0
1985568! Because, 126 x 1.5761
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Factorise 3y^2 - 9y
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5 0
2 years ago
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What is the quotient of (x3 - 3x2 + 5x – 3) = (x - 1)?
IRINA_888 [86]

Note: Consider "÷" sign instead of "=".

Given:

(x^3-3x^2+5x-3)\div (x-1)

To find:

The quotient.

Solution:

We have,

(x^3-3x^2+5x-3)\div (x-1)

It can be written as

=\dfrac{x^3-3x^2+5x-3}{x-1}

Splitting the middle terms, we get

=\dfrac{x^3-x^2-2x^2+2x+3x-3}{x-1}

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Taking out the common factor (x-1), we get

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Cancel the common factors.

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7 0
3 years ago
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masha68 [24]
The answer is the third option
5 0
3 years ago
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Could someone help me? the video doenst explain it
True [87]

Personally, I would recommend reading this as a fraction, and splitting up mantissa from the power of 10. (Mantissa refers to the number 1.23 in 1.23\times10^n.)

\left(3.6 \times 10^{-5}\right) \div \left(9 \times 10^{-7}\right) = \dfrac{3.6 \times 10^{-5}}{9 \times 10^{-7}} = \dfrac{3.6}9 \times \dfrac{10^{-5}}{10^{-7}}

Now just reduce each fraction:

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\left(3.6 \times 10^{-5}\right) \div \left(9 \times 10^{-7}\right) = 0.4 \times 10^2 = \boxed{4 \times 10^1}

since 0.4\times10^2 = 0.4 \times 100 = 40 = 4 \times 10.

7 0
3 years ago
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