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Goryan [66]
3 years ago
8

Carlos walk to school on the 14th of 20 days in February which value is equivalent to the fraction of school days in February th

at Carlos walk to school
Mathematics
1 answer:
Lady bird [3.3K]3 years ago
6 0

Answer:

\dfrac{7}{10}

Step-by-step explanation:

Given that,

Carlos walk to school on the 14th of 20 days in February.

We need to find the equivalent to the fraction of school days in February that Carlos walk to school.

Required percentage is given by :

\%=\dfrac{14}{20}\times 100\\\\=14\times 5\\\\=70\%

or

=\dfrac{7}{10}

So, the required fraction is equal to \dfrac{7}{10}.

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Does the commutative property work for subtraction and division?<br><br><br> no<br><br><br> yes
Ipatiy [6.2K]

Answer:

NO!

Step-by-step explanation:

:-p

6 0
3 years ago
How do i substitute y=x to 3x+2y=20
never [62]
Where ever u see a y change it to an x
3x+2(x)=20
5x=20
x=4
6 0
3 years ago
Read 2 more answers
Write the trigonometric expression <br> Cos (arcsin (u))<br> As an algebraic expression in u
makvit [3.9K]
When we use arcsine, we are finding the angle while giving the trigonometric ratio.

Arcsin(u) = theta can be rewritten as:

sin(theta) = u

Sine is opposite over hypotenuse, so u/1 means that the side opposite to theta (the y value) is u, and the hypotenuse is 1.

We can use Pythagorean Theorem to find the adjacent (x value).

1^2 - u^2 = x^2

x = sqrt(1-u^2)

Back to the original question, we are trying to find cos(arcsin(u)). We just solved all the sides for our triangle using arcsin(u). Now we need to do cos(u).

Cosine is adjacent over hypotenuse.

So our answer is sqrt(1-u^2)/1

Or just sqrt(1-u^2)







5 0
4 years ago
Meg paid $9 for two tuna sandwiches. At the same rate, how much does Meg pay for 8 tuna sandwiches?
sasho [114]
She would pay 36 dollars

6 0
4 years ago
A cookie factory monitored the number of broken cookies per pack yesterday.
trapecia [35]

Answer:

Confidence Interval - 2.290 < S < 2.965

Step-by-step explanation:

Complete question

A chocolate chip cookie manufacturing company recorded the number of chocolate chips in a sample of 50 cookies. The mean is 23.33 and the standard deviation is 2.6. Construct a 80% confidence interval estimate of the standard deviation of the numbers of chocolate chips in all such cookies.

Solution

Given  

n=50

x=23.33

s=2.6

Alpha = 1-0.80 = 0.20  

X^2(a/2,n-1) = X^2(0.10, 49) = 63.17

sqrt(63.17) = 7.948

X^2(1 - a/2,n-1) = X^2(0.90, 49) = 37.69

sqrt(37.69) = 6.139

s*sqrt(n-1) = 18.2

s\sqrt{\frac{n-1}{X^2 _{(n-1), \frac{\alpha }{2} } } \leq \sigma \leq s\sqrt{\frac{n-1}{X^2 _{(n-1), 1-\frac{\alpha }{2} } }

confidence interval:

(18.2/7.948) < S < (18.2/6.139)

2.290 < S < 2.965

8 0
3 years ago
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