Answer:
a. cosθ = ¹/₂[e^jθ + e^(-jθ)] b. sinθ = ¹/₂[e^jθ - e^(-jθ)]
Step-by-step explanation:
a.We know that
e^jθ = cosθ + jsinθ and
e^(-jθ) = cosθ - jsinθ
Adding both equations, we have
e^jθ = cosθ + jsinθ
+
e^(-jθ) = cosθ - jsinθ
e^jθ + e^(-jθ) = cosθ + cosθ + jsinθ - jsinθ
Simplifying, we have
e^jθ + e^(-jθ) = 2cosθ
dividing through by 2 we have
cosθ = ¹/₂[e^jθ + e^(-jθ)]
b. We know that
e^jθ = cosθ + jsinθ and
e^(-jθ) = cosθ - jsinθ
Subtracting both equations, we have
e^jθ = cosθ + jsinθ
-
e^(-jθ) = cosθ - jsinθ
e^jθ + e^(-jθ) = cosθ - cosθ + jsinθ - (-jsinθ)
Simplifying, we have
e^jθ - e^(-jθ) = 2jsinθ
dividing through by 2 we have
sinθ = ¹/₂[e^jθ - e^(-jθ)]
Answer:
The probability that the page will get at least one hit during any given minute is 0.9093.
Step-by-step explanation:
Let <em>X</em> = number of hits a web page receives per minute.
The random variable <em>X</em> follows a Poisson distribution with parameter,
<em>λ</em> = 2.4.
The probability function of a Poisson distribution is:

Compute the probability that the page will get at least one hit during any given minute as follows:
P (X ≥ 1) = 1 - P (X < 1)
= 1 - P (X = 0)

Thus, the probability that the page will get at least one hit during any given minute is 0.9093.
Answer:
from left to right 4,20,25,20
Step-by-step explanation:
20.2 * -2.5ft = -50.5ft
Hence, Winston reach -50.5 feet during his deepest dive.