Answer:
1:13
Step-by-step explanation:
A standard deck has 52 cards not including the joker. each suit has one 10. there are total four "10" in a deck of playing cards. 4/52 = 1/13 or 1:13
Answer:
Total number of outcomes = 23
number of biology and art students = 2
number of biology students = 2
Since it is given that all the students study art,
number of possible outcomes = 2
probability = number of favorable outcomes/number of total outcomes.
= 2/23
Therefore probability that the selected student studies both art and biology is 2/23.
30+5=5+30 with commutative property or 30+5=35
Correct Question : The sum of squares of two consecutive positive odd numbers is 514. Find the numbers.
![\rule{130}1](https://tex.z-dn.net/?f=%5Crule%7B130%7D1)
Solution :
Let the two consecutive positive odd numbers be x and (x + 2)
![\rule{130}1](https://tex.z-dn.net/?f=%5Crule%7B130%7D1)
☯
![:\implies\sf x^2 + (x + 2)^{2} = 514 \\\\\\:\implies\sf x^2 + x^2 + 4x + 4 = 514\\\\\\:\implies\sf 2x^2 + 4x + 4 = 514 \\\\\\:\implies\sf 2x^2 + 4x = 514 - 4\\\\\\:\implies\sf 2x^2 + 4x = 510 \\\\\\:\implies\sf 2x^2 + 4x - 510 = 0\\\\\\:\implies\sf x^2 + 2x - 255 = 0 \:\:\:\:\:\Bigg\lgroup \bf{Dividing\:by\:2}\Bigg\rgroup\\\\\\:\implies\sf x^2 + 17x - 15x - 255 = 0\\\\\\:\implies\sf x(x + 17) - 15(x + 17) = 0\\\\\\:\implies\sf (x + 17) (x - 15)\\\\\\:\implies\sf x = - 17\:or\:x = 15\\\\\\:\implies\underline{\boxed {\sf x = 15}}\:\:\:\:\:\Bigg\lgroup \bf{Positive\:odd\: number}\Bigg\rgroup](https://tex.z-dn.net/?f=%3A%5Cimplies%5Csf%20x%5E2%20%2B%20%28x%20%2B%202%29%5E%7B2%7D%20%3D%20514%20%5C%5C%5C%5C%5C%5C%3A%5Cimplies%5Csf%20x%5E2%20%2B%20x%5E2%20%2B%204x%20%2B%204%20%3D%20514%5C%5C%5C%5C%5C%5C%3A%5Cimplies%5Csf%202x%5E2%20%2B%204x%20%2B%204%20%3D%20514%20%5C%5C%5C%5C%5C%5C%3A%5Cimplies%5Csf%202x%5E2%20%2B%204x%20%3D%20514%20-%204%5C%5C%5C%5C%5C%5C%3A%5Cimplies%5Csf%202x%5E2%20%2B%204x%20%3D%20510%20%5C%5C%5C%5C%5C%5C%3A%5Cimplies%5Csf%202x%5E2%20%2B%204x%20-%20510%20%3D%200%5C%5C%5C%5C%5C%5C%3A%5Cimplies%5Csf%20x%5E2%20%2B%202x%20-%20255%20%3D%200%20%5C%3A%5C%3A%5C%3A%5C%3A%5C%3A%5CBigg%5Clgroup%20%5Cbf%7BDividing%5C%3Aby%5C%3A2%7D%5CBigg%5Crgroup%5C%5C%5C%5C%5C%5C%3A%5Cimplies%5Csf%20x%5E2%20%2B%2017x%20-%2015x%20-%20255%20%3D%200%5C%5C%5C%5C%5C%5C%3A%5Cimplies%5Csf%20x%28x%20%2B%2017%29%20-%2015%28x%20%2B%2017%29%20%3D%200%5C%5C%5C%5C%5C%5C%3A%5Cimplies%5Csf%20%28x%20%2B%2017%29%20%28x%20-%2015%29%5C%5C%5C%5C%5C%5C%3A%5Cimplies%5Csf%20x%20%3D%20-%2017%5C%3Aor%5C%3Ax%20%3D%2015%5C%5C%5C%5C%5C%5C%3A%5Cimplies%5Cunderline%7B%5Cboxed%20%7B%5Csf%20x%20%3D%2015%7D%7D%5C%3A%5C%3A%5C%3A%5C%3A%5C%3A%5CBigg%5Clgroup%20%5Cbf%7BPositive%5C%3Aodd%5C%3A%20number%7D%5CBigg%5Crgroup)
When,
![\bullet\: \textsf {x = } \textbf {15}](https://tex.z-dn.net/?f=%5Cbullet%5C%3A%20%5Ctextsf%20%7Bx%20%3D%20%7D%20%5Ctextbf%20%7B15%7D%20)
![\bullet\: \sf x + 2 = 15 + 2 =\textbf{ 17}](https://tex.z-dn.net/?f=%5Cbullet%5C%3A%20%5Csf%20x%20%2B%202%20%3D%2015%20%2B%202%20%3D%5Ctextbf%7B%2017%7D%20)
![\therefore\:\underline{\textsf{The required positive integer is \textbf{15 and 17}}}.](https://tex.z-dn.net/?f=%5Ctherefore%5C%3A%5Cunderline%7B%5Ctextsf%7BThe%20required%20positive%20integer%20is%20%5Ctextbf%7B15%20and%2017%7D%7D%7D.)
Answer:
c
Step-by-step explanation: