All categories

3 years ago

A cylinder soup has a radius of 1,6 in and is 5/7 in. tall what is the volume

Mathematics

1 answer:

nata0808 [166]3 years ago

6 0

Answer:

$V=0.0623\ inch^3$

Step-by-step explanation:

Given that,

The radius of cylinder, r = 1/6 inch

The height of the cylinder, h = 5/7 inch

We need to find the volume of the cylinder. The formula for the volume of a cylinder is given by :

$V=\pi r^2 h\\\\=3.14\times (\dfrac{1}{6})^2\times \dfrac{5}{7}\\\\V=0.0623\ inch^3$

So, the volume of the cylinder is equal to $0.0623\ inch^3$ .

You might be interested in

Find the indefinite integral. (Note: Solve by the simplest method—not all require integration by parts. Use C for the constant o

umka2103 [35]

Answer:

∫▒〖arctan⁡(x).1 dx=arctan⁡(x).x〗-1/2 ln⁡(1+x^2 )+C

Step-by-step explanation:

∫▒〖1st .2nd dx=1st∫▒〖2nd dx〗-∫▒〖(derivative of 1st) dx∫▒〖2nd dx〗〗〗

Let 1st=arctan⁡(x)

And 2nd=1

∫▒〖arctan⁡(x).1 dx=arctan⁡(x) ∫▒〖1 dx〗-∫▒〖(derivative of arctan(x))dx∫▒〖1 dx〗〗〗

As we know that

derivative of arctan(x)=1/(1+x^2 )

∫▒〖1 dx〗=x

∫▒〖arctan⁡(x).1 dx=arctan⁡(x).x〗-∫▒〖(1/(1+x^2 ))dx.x〗…………Eq1

Let’s solve ∫▒(1/(1+x^2 ))dx by substitution now

Let 1+x^2=u

du=2xdx

Multiply and divide ∫▒〖(1/(1+x^2 ))dx.x〗 by 2 we get

1/2 ∫▒〖(2/(1+x^2 ))dx.x〗=1/2 ∫▒(2xdx/u)

1/2 ∫▒(2xdx/u) =1/2 ∫▒(du/u)

1/2 ∫▒(2xdx/u) =1/2 ln⁡(u)+C

1/2 ∫▒(2xdx/u) =1/2 ln⁡(1+x^2 )+C

Putting values in Eq1 we get

∫▒〖arctan⁡(x).1 dx=arctan⁡(x).x〗-1/2 ln⁡(1+x^2 )+C (required soultion)

3 0

3 years ago

Read 2 more answers

Tommy has 5 jars of marble. Each Jar is filled 2/3 with marbles. How many full Jars does tommy have? Make a model and shade in t

ivann1987 [24]

5 / ( 2 / 3 ) = 7.5

7 full jars

6 0

2 years ago

Here is a list of numbers: 7.3, 4.2, 7.3, 6.7, 4.2, 9.3, 1.2 ,1.1 ,6.4 ,8 State the median.

morpeh [17]

First order the numbers then cross out the numbers till in the middle the numbers 6.4 and 6.7 add then divide by two to get the middle and the median
13.1/2 =6.55

Answer:6.55

1.1
1.2
4.2
4.2
6.4
6.7
7.3
7.3
8
9.3

6 0

3 years ago

These are the options (0,-5) (4,-2) (8,2) (-16,-17) (-1,-8) (-40,-34)

Liono4ka [1.6K]

All you need to do is plug in the points!

Here we go:

3(0)- 4(-5)-8

If it equals 12, then it is a point and an answer.

3(0)- 4(-5)-8= 12

(0,-5) is a point!

Next one:

3(4)-4(-2)-8

12+8-8
That equals twelve. (4,-2) is an answer as well!

I am going to quickly plug in the rest of the points, since I think you have the idea.
(8,2) 3(8)-4(2)-8= 8 This is not an answer.
(-16,-17) 3(-16)-4(-17)-8 = 12 This is answer.
(-1,-8) 3 (-1)-4(-8)-8= 21 This is not an answer.
(-40,-34) 3(-40)-4(-34)-8= 8 This is not an answer.

I hope this helped you!

Brainliest answer is always appreciated!

3 0

3 years ago

The midpoint of AB ‾ AB is M ( 3 , − 2 ) M(3,−2). If the coordinates of A A are ( 1 , − 3 ) (1,−3), what are the coordinates of

mina [271]

We can find out AM. We have to do 0M - 0A which will give (2, -5)
Now w can take 2* AM

7 0

3 years ago